If 115grams of a substance reacts with 84grams of another substance, what will be the mass of the products after the reaction?

The reaction for the formation of phosgene from carbon monoxide and chlorineCO + Cl2 --> COCl2 is first order in CO and secon

Ilya [14]

Answer:

$r = k . [CO] .[Cl_{2}]$

Explanation:

Let´s consider the following reaction:

CO + Cl₂ ⇒ COCl₂

The general rate law is:

$r = k . [CO]^{m}. [Cl_{2}]^{n}$

where,

r is the rate of the reaction

k is the rate constant

[CO] and [Cl₂] are the molar concentrations of each reactant

m and n are the reaction orders for each reactant

Since the reaction is first order in CO, m = 1. The overall order is the sum of all the individual orders. In this case, the overall order m + n = 2. Then,

m + n = 2

n = 2 - m = 2 - 1 = 1

The reaction is first order in Cl₂.

The rate law is:

$r = k . [CO]. [Cl_{2}]$

6 0

4 years ago

Trichinella spiralis the worm that causes trichinosis is a what kind of worm

Fudgin [204]

It's a parasite. Hope I helped!

8 0

3 years ago

A solution is made by dissolving 100. g of cobalt(III)chloride in 250. g of water. to make a solution that has a density of 1.25

Mariulka [41]

Answer:

Option A) (I) 2.42 m (II) 2.16 M

Explanation:

Let's determine some information.

Solute = CoCl₃ (molar mass = 165.29 g/m); mass of 100 g

Solvent = Water, mass of 250 g

Solution mass = mass of CoCl₃ + mass of water

250 g + 100 g = 350 g of solution

If we want to reach molarity (mol/L), let's determine solution volume with density:

Solution density = solution mass / solution volume

1.25 g/mL = 350 g / solution volume

Solution volume = 350 g / 1.25 g/mL = 280 mL

Let's convert the volume to L → 280 mL = 0.280L

Let's convert the mass of solute to moles = 100 g / 165.29 g/m →0.605 mol

Mol/L = 0.605 moles / 0.280 L = 2.16 M

Now let's calculate molalilty (mol/kg of solvet)

We must convert solvent mass to kg → 250g = 0.250 kg

Then, 0.605 moles / 0.250 kg =2.42 m

8 0

4 years ago

Calculate the amount of heat needed to boil 120.g of acetic acid (HCH3CO2), beginning from a temperature of 16.7°C.

evablogger [386]

Answer:

The total amount of heat needed = 72.2116 kJ

Explanation:

Given that ;

the mass of acetic acid = 120.0 g

The initial temperature $T_1$ = 16.7 °C = (16.7 + 273.15 ) K = 298.85 K

The standard molar mass of acetic acid = 60.052 g/mol

Thus ; we can determine the number of moles of acetic acid;

number of moles of acetic acid = mass of acetic acid/ molar mass of acetic acid

number of moles of acetic acid = 120.0 g/ 60.052 g/mol

number of moles of acetic acid = 1.998 moles

For acetic acid:

The standard boiling point $T_2$ = 118.1 °C = ( 118.1 + 273.15 ) K = 391.25 K

The enthalpy of vaporization of acetic acid $\Delta H_{vap}$ = 23.7 kJ/mol

The heat capacity of acetic acid c = 2.043 J/g.K

The change in temperature Δ T = $T_2 - T_1$

Δ T = (391.25 - 289.85)K

Δ T = 101.4 K

The amount of heat needed to bring the liquid acetic acid at 16.7°C to its boiling point is ;

q = mcΔT

From our values above;

q = 120 g × 2.043 J/g.K × 101.4 K

q = 24859.2 J

q = 24859 /1000 kJ

q = 24.859 kJ

we have earlier calculated our number of moles o f acetic acid to be 1.998 moles;

Thus;

The needed amount of heat = $\Delta_{vap} *numbers \ of \ moles$

The needed amount of heat = $23.7 \ kJ/mol * 1.998 \ moles$

The needed amount of heat = 47.3526 kJ

Hence;

The total amount of heat needed = 24.859 kJ + 47.3526 kJ

The total amount of heat needed = 72.2116 kJ

4 0

3 years ago

what mass of copper is produce when Zinc is added to a solution containing 31.9g copper (ii) tetraoxosulphate (vi)

Sergio [31]

12.7 grams of copper will be produced.

<h3><u>Explanation</u>:</h3>

Copper is placed below zinc in the metal activity series. This means zinc can replace copper from its salt. Here zinc is added to the salt solution of copper sulphate. The reaction involved is

CuSO4 +Zn =ZnSO4 +Cu.

Zinc sulphate is soluble in the solution and rose red copper will be precipitated from the solution.

From the chemical equation we can see that 1 mole of zinc replaces 1 mole of copper. As no mass of zinc added is mentioned we will assume that excess of zinc is added.

Atomic mass of copper = 63.5

Atomic mass of sulphur = 32.

Atomic mass of oxygen = 16.

So molecular mass of copper sulphate = $63.5 + 32 + 4\times16$ = 159.5.

So, mass of 1 mole of copper sulphate is 159.5 grams.

So, in 31.9 grams of copper sulphate, number of moles of copper sulphate present = $\frac {159.5}{31.9}$ = 0.2

In 1 mole of copper sulphate, 1 mole of copper is present.

So in 0.2 moles of copper sulphate, 0.2 moles of copper is present.

So mass of 0.2 moles of copper = $0.2\times63.5$ = 12.7 grams

8 0

4 years ago