Answer:
The correct option is e.
Explanation:
p-value is the probability value for a given statistical model, the probability that, when the null hypothesis is true.
For two two samples the formula of test statistics is

where,
is sample mean
is population mean.
is standard deviation.
n is sample size.
Variance is the square of standard deviation.
It means variance, mean, numbers of samples is used in calculation of p-value.
Degree of freedom define the shape of the t-distribution that your t-test uses to calculate the p-value.

p-value of a statistical test depends on all of the following, except median.
Therefore the correct option is e.
Answer:
There are 0,011 moles of hydrogen gas.
Explanation:
We use the ideal gas formula, with the constant R = 0.082 l atm / K mol. The STP conditions are : 1 atm pressure and 273 K temperature. Solve for the formula, n (number of moles):
PV=nRT ---> n= (PV)/(RT)
n= (1 atm x 0,25 L)/ (0,082 l atm/ K mol x 273 K)
<em>n= 0,011 mol</em>
Answer:
Noble Gases are very stable because...
1) Noble Gases have a full octet
2) Low chemical reactivity
Explanation:
This means that is has 8 valence electrons so it won't need any more, so it is less likely to react with other substances.
Burette is a very accurate measuring instrument when adding solutions and has a measurement error of 0.05 mL.
Small volumes of solutions can be transferred from the burette at a controllable rate.
In this instance NaOH is in the burette.
Initial reading of NaOH is 0.20 mL
end point is the point at which the chemical reaction reaches completion. In acid base reactions, end point is when all the H⁺ ions have reacted with OH⁻ ions.
final reading of NaOH is 24.10 mL
to find the volume of NaOH dispensed we have to find the difference between final reading and initial reading
volume of NaOH added = 24.10 mL - 0.20 mL = 23.90 mL
volume of NaOH dispensed is 23.90 mL
13111 is already an integer (whole number). It also can be expressed as 1 ton or 13111000g.