Answer:
Explanation:
We are given that 25 mL of 0.10 M 
is titrated with 0.10 M NaOH(aq).
We have to find the pH of solution
Volume of 
Volume of NaoH=0.01 L
Volume of solution =25 +10=35 mL=
Because 1 L=1000 mL
Molarity of NaOH=Concentration OH-=0.10M
Concentration of H+= Molarity of 
=0.10 M
Number of moles of H+=Molarity multiply by volume of given acid
Number of moles of H+=
=0.0025 moles
Number of moles of 
=0.001mole
Number of moles of H+ remaining after adding 10 mL base = 0.0025-0.001=0.0015 moles
Concentration of H+=
pH=-log [H+]=-log [4.28
]=-log4.28+2 log 10=-0.631+2
Answer : The mass of lithium hypochlorite are, 34.7 grams.
Explanation : Given,
Moles of 
= 0.594 g
Molar mass of = 58.4 g/mol
Expression used :
Now put all the given values in this expression, we get:
Therefore, the mass of lithium hypochlorite are, 34.7 grams.
Answer:
a) v = 1497.2 cm^-1
b) v = 1465 cm^-1
Explanation:
In the attached image is the procedure explained to reach the answer.
Answer: false
Explanation:
It is false that to study Earth's interior, geologists often rely on indirect methods, such as evidence from fossils. They rely on seismic wave.
<span>because p6 will be the group 8. You have to count the 2 electrons from the "s" block that are Group I and Group II
Group I s1
Group II s2
Group III s2 p1
Group IV s2 p2
Group V s2 p3
Group VI s2 p4
Group VII s2 p5
Group VIII s2 p6</span>
