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3 years ago

Carbon dioxide is formed when two oxygen atoms chemically combine with a carbon atom. Which term best describes carbon dioxide?

Chemistry

2 answers:

klemol [59]3 years ago

5 0

Answer:

compound

Explanation:

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viktelen [127]3 years ago

4 0

Answer:

CO2 is formed when two oxygen atoms chemically combine with a carbon atom. So therefore the correct answer would be D, compound.

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To fulfill the octet rule electron sharing leads to ____ electrons around each atom?

Dimas [21]

D. 8

You can predict it from it's name "Octet" means Eight. Atom must have that number of electron to have a stable structure!

Hope this helps!

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3 years ago

Read 2 more answers

What do the arrows in the diagram tell you about the molecule?

maw [93]

Answer:

Explanation:

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3 years ago

What element does gold identity as

ICE Princess25 [194]

Gold is a chemical element with symbol Au (from Latin: aurum) and atomic number 79, making it one of the higher atomic number elements that occur naturally. In its purest form, it is a bright, slightly reddish yellow, dense, soft, malleable, and ductile metal.

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3 years ago

Calculate hydrochloric acid (umol)in 200 ul of a<br> 0.5173Msolution of acid?

strojnjashka [21]

<u>Answer:</u> The moles of hydrochloric acid is $1.0346\times 10^{-4}\mu mol$

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Or,

$\text{Molarity of the solution}=\frac{\text{Micro moles of solute}\times 10^6}{\text{Volume of solution (in }\mu L)}}$

We are given:

Molarity of solution = 0.5173 M

Volume of solution = $200\mu L$

Putting values in above equation, we get:

$0.5173M=\frac{\text{Micro moles of HCl}\times 10^6}{200\mu L}\\\\\text{Micro moles of HCl}=1.0346\times 10^{-4}\mu mol$

Hence, the moles of hydrochloric acid is $1.0346\times 10^{-4}\mu mol$

7 0

3 years ago

a student reacted 40 drops of an unknown amine with 20 drops of iodomethane in 2 ml of a suitable solvent mixture. after 15 minu

lutik1710 [3]

The compound formed is the quaternary ammonium salt N,N,N-trimethyl-1-phenylmethanaminium iodide.

Quaternary ammonium salts are formed when methyl iodide reacts with an amine. The quaternary ammonium salt is an ionic substance which often has a high melting point. Remember that the melting point of a substance can be used to identify the substance.

In this case, a student reacted 40 drops of an unknown amine with 20 drops of iodomethane in 2 ml of a suitable solvent mixture. after 15 minutes of reaction, a white precipitate formed. the precipitate was isolated and its melting point was recorded to be 178 °c. This precipitate must be N,N,N-trimethyl-1-phenylmethanaminium iodide (Benzyltrimethylammonium iodide) because it is a quaternary ammonium salt whose melting point is 178 °c.

Learn more: brainly.com/question/5325004

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2 years ago