Two partial cells, which are still forming into real cells
Answer:
The correct option is B) Their offspring cannot breed.
Explanation:
Organisms belonging to the same species require the ability to breed and produce fertile offsprings. If two organisms breed to produce infertile offsprings, then they are not considered to belong in the same species. Infertile offsprings do not have the capability to reproduce. The breeding between a horse and a zebra produces zorse, which is sterile. This depicts that both the zebra and horse belong to different species as they cannot produce a fertile offspring.
Answer:
6,25%
Explanation:
Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:
Parents: Aa X Aa
Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)
Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:
A x A = 1/4 = 25%
A x a = 1/4 = 25%
a x A = 1/4 = 25%
a x a = 1/4 = 25%
The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:
1/4 × 1/4 = 1/16 = 0.0625 = 6.25%
It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.
Answer:
45 g of the solid Tris will be dissolved in 2.5 liters of water.
Explanation:
Recall that:
<em>Number of moles = molarity x volume</em>
Hence, number of moles of Tris present in 2.5 liters, 150 mM solution:
= 150/1000 x 2.5 = 0.375 moles
Also, recall that:
<em>No of moles of substance = mass/molar mass.</em>
Hence, mass of 0.375 moles substance:
= no of moles of the substance x molar mass of the substance.
= 0.375 x 120 = 45 g.
Therefore, in order to prepare 2.5 liters, 150 mM of an aqueous solution of Tris, 45 g of the solid Tris will be dissolved in 2.5 liters of water.
