What's the question? there isn't enough info to help.
We can factor by grouping. To do so, we multiply the leading coefficient with the constant at the end. In other words, a times c (ax^2 + bx + c).
15*-4 = -60
Now we need to split the b term into two pieces that multiply to -60 and add to 4.
-6 and 10 will work.
Now group one part of b with the 15x^2 and the other part with -4.
(15x^2 + 10x) + (-6x - 4)
Now factor both terms.
5x(3x+2) - 2(3x+2)
3x+2 is one of our factors and 5x-2 is the other.
(3x+2)(5x-2)=0
Now just find the zeros.
3x+2 = 0
3x = -2
x = -2/3
And
5x-2 = 0
5x = 2
x = 2/5
So the answer is x = -2/3 and x = 2/5
The air force plane travelled for a total of 6.9 hours.
<u>SOLUTION:
</u>
Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph. A cargo plane left sometime later flying in the same direction at an average speed of 207 mph. After flying for 5.3 hours the cargo plane caught up with the Air Force plane.
We have to find the number of hours the Air Force plane flew before the cargo plane caught up.
Now, we know that, 
For air force plane 

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.
So, 


Time taken by air force plane = 6.9 hrs
Answer:
(f+g)(2) = 10
Step-by-step explanation:
f(x)=2x^2+3x
g(x)=x-2
(f+g)(x) will be sum of f(x) and g(x)
(f+g)(x) = 2x^2+3x + x - 2 = 2x^2+4x - 2
we have to find (f+g)(2), for that we will put x = 2
(f+g)(x) = 2x^2+4x - 2

Thus, (f+g)(2) is 10.
Answer:
14256
Step-by-step explanation:
- 10/100×15840=1584
- 15840-1584=14256
- Answer =14256