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ICE Princess25 [194]
3 years ago
8

Evaluate 5t + 4 if t=3 PLEASE HURRY! I'M TIMED!

Mathematics
1 answer:
Wittaler [7]3 years ago
4 0
Substitute the value of the variable into the equation and simplify.
19
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3 years ago
Write the standard equation of the circle with center (– 10, –3) that passes through the point (-3,3).
Sphinxa [80]

Answer:

(x+10)^2 + (y+3)^2 = 85

Step-by-step explanation:

Equation of a circle:

The standard equation of a circle with center (x_0,y_0) is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

In which r is the radius.

Center (– 10, –3)

This means that x_0 = -10, y_0 = -3. So

(x - x_0)^2 + (y - y_0)^2 = r^2

(x - (-10))^2 + (y - (-3))^2 = r^2

(x+10)^2 + (y+3)^2 = r^2

Passes through the point (-3,3).

This means that we use x = -3, y = 3 to find the radius squared. So

(x+10)^2 + (y+3)^2 = r^2

(-3+10)^2 + (3+3)^2 = r^2

r^2 = 49 + 36

r^2 = 85

The equation of the circle is:

(x+10)^2 + (y+3)^2 = r^2

(x+10)^2 + (y+3)^2 = 85

7 0
3 years ago
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