3 years ago

Why does the United kingdom have a temperate climate instead of a polar climate

1 answer:

6 0

Answer:

https://www.bbc.co.uk/bitesize/guides/zpykxsg/revision/3 (i know ppl hate it when you put links but i actually think this may explain it)

Explanation:

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At 298 K the standard enthalpy of combustion of sucrose is -5645 kJ/mol and the standard reaction Gibbs energy is -5798 kJ/mol.

natka813 [3]

Explanation:

The given data is as follows.

T = 298 K, $\Delta H^{o}$ = -5645 kJ/mol

$\Delta G^{o}$ = -5798 kJ/mol

Relation between $\Delta H$ and $\Delta G$ are as follows.

$\Delta G^{o}$ = $\Delta H^{o} - T \Delta S^{o}$

-5798 kJ/mol = -5645 kJ/mol - $298 \times \Delta S^{o}$

-153 kJ/mol = - $298 \times \Delta S^{o}$

$\Delta S^{o}$ = 0.513 kJ/mol K

Now, temperature is $37^{o}C$ = (37 + 273) K = 310 K

Since, $\Delta G$ = $\Delta H^{o} - T \Delta S^{o}$

= $-5645 kJ/mol - 310 K \times 0.513 kJ/mol K$

= (-5645 kJ/mol - 159.03 kJ/mol)

= -5804.03 kJ/mol

As, change in Gibb's free energy = maximum non-expansion work

$\Delta G = \Delta G_{310 K} - \Delta G_{298 K}$

= -5804.03 kJ/mol - (-5798 kJ/mol)

= -6.03 kJ/mol

Therefore, we can conclude that the additional non-expansion work is -6.03 kJ/mol.

5 0

3 years ago

A helium balloon at 23 C has a volume of 755 mL. The balloon is placed into a freezer kept at -10 C. Assuming pressure is consta

Vera_Pavlovna [14]

Explanation:

T1/V1 = T2/V2

V2 = T2 x V1/T1

V2 = 296.15x535/319.15

V2 = 496.44mL

5 0

3 years ago

A pot filled with snow is left on a hot stove for a while. What would happen?

s2008m [1.1K]

Answer:

it will melt

Explanation:

because the heat will observe it and melt

7 0

3 years ago

Answer plss really appreciate it

monitta

No. Only the state is changed.

6 0

3 years ago

Sasha did an experiment to study the solubility of two substances. She poured 100 mL of water at 20°C

Gwar [14]

Answer:

it would be 78 degrees higher

Explanation:

7 0

3 years ago