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Ludmilka [50]
3 years ago
9

The specific heat of zinc is 0.39 J/g*°C. How much energy needed to change the temperature of 34g of zinc from 22°C to 57°C. Is

the energy absorbed or released? 464.1 J, absorbed 464.1 J, released 928.2 J, absorbed 928.2 J, released
Chemistry
1 answer:
Svetlanka [38]3 years ago
6 0

Answer:

464.1 J absorbed.

Explanation:

Given data:

Specific heat of zinc =  0.39 J/g°C

Mass of zinc = 34 g

Temperature changes = 22°C to 57°C

Energy absorbed or released = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 57°C -  22°C

ΔT = 35°C

Q = m.c. ΔT

Q = 34 g. 0.39 J/g°C. 35°C

Q = 464.1 J

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3 years ago
How many milliliters of 2.19 M H2SO4 are required to react with 4.75 g of solid containing 21.6 wt% Ba(NO3)2 if the reaction is
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Answer:

1.7927 mL

Explanation:

The mass of solid taken = 4.75 g

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Mass of Ba(NO_3)_2 = \frac {21.6}{100}\times 4.75\ g = 1.026 g

Molar mass of Ba(NO_3)_2 = 261.337 g/mol

The formula for the calculation of moles is shown below:

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Thus,

Moles= \frac{1.026\ g}{261.337\ g/mol}

Moles= 0.003926\ mol

Considering the reaction as:

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1 moles of Ba(NO_3)_2 react with 1 mole of H_2SO_4

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Moles of H_2SO_4 = 0.003926 mole

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