A pot filled with snow is left on a hot stove for a while. What would happen?

The value of ΔG° at 181.0 °C for the formation of calcium chloride from calcium metal and chlorine gas is ________ kJ/mol. At 25

aleksandr82 [10.1K]

Answer:

$\Delta G^{0}$ at 181.0 $^{0}\textrm{C}$ is -723.3 kJ/mol.

Explanation:

We know, $\Delta G^{0}=\Delta H^{0}-T\Delta S^{0}$

where, T is temperature in kelvin.

Let's assume $\Delta H^{0}$ and $\Delta S^{0}$ does not change in the temperature range 25.0 $^{0}\textrm{C}$ - 181.0 $^{0}\textrm{C}$ .

$181.0^{0}\textrm{C}$ = (273+181.0) K = 454.0 K

Hence, at 181.0 $^{0}\textrm{C}$ , $\Delta G^{0}=(-795.8kJ/mol)-[(454.0 K)\times (-159.8\times 10^{-3}kJ/K.mol)]$

= -723.3 kJ/mol

5 0

2 years ago

What will happen to convection currents in the mantle if earths interior eventually cools down?

VLD [36.1K]

If the core were to cool completely, the planet would grow cold and dead. It also would get a little dark: Power utilities pull radiant heat from Earth's crust and use it to heat water, the steam from which powers turbines to create electricity.Cooling also could cost us the magnetic shield around the planet created by heat from the core. This shield protects Earth from cosmic radiation. The shield is created by a convection process caused by constantly moving iron. Like the planet itself, Earth's core is constantly spinning. Some scientists think it's moving even faster than the rest of the planet. The friction converts kinetic energy into electrical and magnetic energy that forms the field, which deflects harmful, charged particles emanating from the sun toward the north and south poles. Your welcome :)

6 0

3 years ago

A solution of phosphoric acid was made by dissolving 10.0 g of H3PO4 in 100.0 mL of water. The resulting volume was 113 mL. Calc

rodikova [14]

Explanation:

Mass of solute = 10.0 g

mass of solvent(water) = m

Volume of solvent( water) = v = 100.0 mL

Density of water= d = $1 g/cm^3=1 g/mL$

$1 mL= 1 cm^3$

$m=d\times v=1.0 g/mL\times 100.0 = 100.0 g$

Mass of solution(M) = Mass of solute + mass of solvent

M = 10.0 g + 100.0 g = 110.0 g

Volume of the solution = V = 113 mL

Density of the solution = D

$D=\frac{M}{V}=\frac{110.0 g}{113 mL}=0.9734 g/mL$

The density of the solution is 0.9734 g/ml.

Moles of phosphoric acid = $n_1=\frac{10.0 g}{98 g/mol}=0.1020 mol$

Moles of water = $n_2=\frac{100.0 g}{18g/mol}=5.556 mol$

Mole fraction of phosphoric acid = $\chi_1$

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.1020 mol}{0.1020 mol+5.556 mol}$

$\chi_1=0.01803$

Mole fraction of water = $\chi_2$

$\chi_2=\frac{n_2}{n_1+n_2}=\frac{5.556 mol}{0.1020 mol+5.556 mol}$

$\chi_2=0.9820$

$[Molarity]=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}$

Moles of phosphoric acid = 0.1020 mol

Volume of the solution = V = 113 mL = 0.113 L ( 1 mL = 0.001 L)

Molarity of the solution :

$=\frac{0.1020 mol}{0.113 L}=0.903 M$

$[Molality]=\frac{\text{Moles of solute}}{\text{Mass of solvent(kg)}}$

Moles of phosphoric acid = 0.1020 mol

Mass of solvent(water) = m =100.0 g = 0.100 kg ( 1 g = 0.001 kg)

Molality of the solution :

$=\frac{0.1020 mol}{0.100 kg}=1.02 mol/kg$

6 0

2 years ago

All the elements in period 3 have this characteristic

Studentka2010 [4]

Answer:

The answer would be C). All of the elements inside a period will always have the same amount of shells. Hope this helps!

7 0

2 years ago

Read 2 more answers

Solve fasttt<br><br> C7H17+O2=CO2+H2O<br><br> Balancing Equations

sertanlavr [38]

Answer:

The answer to your question is

4C₇H₁₇ + 45 O₂ ⇒ 28 CO₂ + 34H₂O

Explanation:

Write the equation

C₇H₁₇ + O₂ ⇒ CO₂ + H₂O

Process

1.- Check if the equation is balanced

Reactants Element Products

7 C 1

17 H 2

2 O 3

As the number of reactants and products is different, we conclude that the reaction is unbalanced.

2.- Write a coefficient "7" to CO₂ and a coefficient of 17/2 to H₂O

C₇H₁₇ + O₂ ⇒ 7CO₂ + $\frac{17}{2}$ H₂O

Reactants Element Products

7 C 7

17 H 17

2 O 51/2

3.- Write a coefficient of 45/2 to the O₂, and multiply all the equation by 2.

4C₇H₁₇ + 45 O₂ ⇒ 28 CO₂ + 34H₂O

Reactants Element Products

28 C 28

68 H 68

90 O 90

5 0

2 years ago