Neon = app. 20.1795 g/mol
<span>Bromine = app. 79.904 g/mol </span>
<span>-----> 79.904 g/mol / 20.1795 g/mol = 3.96 (Close to 4) </span>
<span>Using Moles In 1000 g </span>
<span>1000 g / 20.1795 g/mol = app. 49.555 mol of Ne </span>
<span>1000 g / 79.904 g/mol = app. 12.515 mol of Br </span>
<span>-----> 49.555 mol / 12.515 mol = 3.96 (Close to 4) </span>
<span>Using Avogadro's Number </span>
<span>49.555 mol x 6.022x10^23 atoms = app. 2.984x10^25 atoms of Ne </span>
<span>12.515 mol x 6.022x10^23 atoms = app. 7.537x10^24 atoms of Br </span>
<span>-----> 2.984x10^25 / 7.537x10^24 = 3.96 (Close to 4) </span>
<span>So no matter how you look at it or calculate it, the answer is always the same. </span>
<span>I hope it helps!</span>
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<u>Answer:</u> The symbol of the ion formed is 
<u>Explanation:</u>
An ion is formed when a neutral atom looses or gains electrons.
- When an atom looses electrons, it results in the formation of positive ion known as cation.
- When an atom gains electrons, it results in the formation of negative ion known as anion.
Electronic configuration is defined as the representation of electrons around the nucleus of an atom.
Number of electrons in an atom is determined by the atomic number of that atom.
The element present in Group 2-A and in period 4 is Calcium (Ca)
Electronic configuration of Ca atom: 
This atom will loose 2 electrons to attain stable electronic configuration similar to Argon element (noble gas)
The electronic configration of 
Hence, the symbol of the ion formed is
Answer:The computer writes electron configurations in the form, for Co for example, [Ar]3d(7)4s(2), which we would write [Ar]3d74s2
NOTE: Write electron configurations as they appear in the periodic table in the front of you text put 4f before 5d
Explanation:
Answer:
SO4 (aq) + Sr (aq) >> SrSO4 (s)
Explanation:
K+1 SO4-2 + Sr +2 I2- >> sK +1
(you dont separate and write down the ions for Sr SO4 because its a solid)
Cancel out the same ions from both sides and write down what your left with.
