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Trava [24]
4 years ago
6

What value(s) of x will make x2 = 36 true?

Mathematics
2 answers:
Marina CMI [18]4 years ago
6 0

Answer:

x²=36

x²=6²

equating both squares

x=6

so, b is correct answer

Digiron [165]4 years ago
5 0

Answer:   option B.  6

Step-by-step explanation: x = 6

x^2 = 36

6 x 6 = 36

Hope it helped u, pls mark as the brainliest and put thanks for the ans

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3 years ago
Write the equation of a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2(sqrt5)
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Answer:

\frac{x^2}{16}-\frac{b^2}{4}=1

Step-by-step explanation:

A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.

The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1

The coordinates of the foci is at (±c, 0), where c² = a² + b²

Given that  a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\frac{4^2}{a^2}-\frac{0}{b^2} =1\\\frac{4^2}{a^2}=1\\ a^2=16\\a=\sqrt{16}=4\\ a=4

The foci c is at +/-2√5, using c² = a² + b²:

c^2=a^2+b^2\\(2\sqrt{5} )^2=4^2+b^2\\20 = 16 + b^2\\b^2=20-16\\b^2=4\\b=\sqrt{4}=2\\ b=2

Substituting the value of a and b to get the equation of the hyperbola:

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\\\frac{x^2}{16}-\frac{b^2}{4}=1

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