2 years ago

What is the solution to log Subscript 5 Baseline (10 x minus 1) = log Subscript 5 Baseline (9 x + 7)

2 answers:

5 0

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$\sf{log_{5}}(\tt{10x-1})=\sf{log_{5}}(\tt{9x+7})\\\\10x-1=9x+7\\\\10x-9x=7+1\\\\\pmb{\green{\underline{\sf{x=\frak{8}}}}}$

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zimovet [89]2 years ago

4 0

Answer:

x = 8

Step-by-step explanation:

Given:

log₅ (10x - 1) = log₅ (9x + 7)
10x - 1 = 9x + 7
10x - 9x = 7 + 1
x = 8

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