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dem82 [27]
3 years ago
11

a group 5 friends want to buy a flat screen tv for $ 210. the tax comes to $15. write and solve a multiplication equation to fin

d how much money each person should pay if each person pays the same amount. explain your reasoning.
Mathematics
2 answers:
Greeley [361]3 years ago
7 0

Let x be the amount each friend pays .

There are five friends contributing ,so 5x will be the total money collected .

It needs to equal the price plus the tax, 210 + 15 = 225

So the equation becomes,

5x = 210 + 15

5x = 225

dividing right side by 5, we have

x = 225/5 = 45

Answer: So each frien pays $45.

lyudmila [28]3 years ago
3 0

Let x be the amount each pays

5x will be the total money collected

It needs to equal the price plus the tax, 210 + 15

5x = 210 + 15

5x = 225

x = 225/5 = 45

Answer: $45 each

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When Brooklyn runs the 400 meter dash, her finishing times are normally distributed with a mean of 76 seconds and a standard dev
KonstantinChe [14]

Using the Empirical Rule, it is found that her finishing time will be between 70 and 82 seconds in 95% of her races.

<h3>What does the Empirical Rule state?</h3>

It states that, for a normally distributed random variable:

  • Approximately 68% of the measures are within 1 standard deviation of the mean.
  • Approximately 95% of the measures are within 2 standard deviations of  the mean.
  • Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, the mean is of 76 seconds and the standard deviation is of 3 seconds, then:

76 - 2 x 3 = 70.

76 + 2 x 3 = 82.

Which means that values between 70 and 82 seconds are within 2 standard deviations of the mean, hence the percentage is of 95%.

More can be learned about the Empirical Rule at brainly.com/question/24537145

3 0
2 years ago
My life is helpless.... could you please help? i cant even understand this I'm only 10.
Nadya [2.5K]
I think the equation is y= -1/3x+1. The slope is going down, so it’s negative. And the y intercept is 1. And how I got a fraction is by using rise/run.
5 0
3 years ago
A circle with radius of 4cm sits inside a circle with radius of 11cm.
sweet-ann [11.9K]

Answer:

Area of shaded region = 329.70 cm²

Step-by-step explanation:

Area of a circle = πr²

Area of bigger circle = 3.14 × 11²

= 3.14 × 11 × 11

= 379.94 cm²

Area of smaller circle = 3.14 * 4²

= 3.14 × 4 × 4

= 50.24 cm²

Area of shaded region

= Area of bigger circle - Area of smaller circle

= (379.94 - 50.24) cm²

= 329.70 cm²

6 0
3 years ago
Which expression has a base with the exponet of 4?
vova2212 [387]

Answer:

4z²

Step-by-step explanation:

isksnvejdlebeislsvwyyq8qksbsyessdhdomdnxbxvhsisisnsbdgdydos

7 0
3 years ago
A researcher wishes to see if the five ways (drinking decaffeinated beverages, taking a nap, going for a walk, eating a sugary s
e-lub [12.9K]

Answer:

\chi^2 = \frac{(21-12)^2}{12}+\frac{(16-12)^2}{12}+\frac{(10-12)^2}{12}+\frac{(8-12)^2}{12}+\frac{(5-12)^2}{12}=13.833

p_v = P(\chi^2_{4} >13.833)=0.00785

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(13.833,4,TRUE)"

Since the p value is lower than the significance level we can reject the null hypothesis at 5% of significance, and we can conclude that the  drowsiness are NOT equally distributed among office workers .

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Method   Beverage   Nap   Walk   Snack   Other

Number       21             16       10         8         5

The total on this case is 60

We need to conduct a chi square test in order to check the following hypothesis:

H0: Drowsiness are equally distributed among office workers

H1: Drowsiness IS NOT equally distributed among office workers

The level of significance assumed for this case is \alpha=0.1

The statistic to check the hypothesis is given by:

\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total}{5}

And the calculations are given by:

E_{Beverage} =\frac{60}{5}=12

E_{Nap} =\frac{60}{5}=12

E_{Walk} =\frac{60}{5}=12

E_{Snack} =\frac{60}{5}=12

E_{Other} =\frac{60}{5}=12

And the expected values are given by:

Method   Beverage   Nap   Walk   Snack   Other

Number       12             12       12         12         12

And now we can calculate the statistic:

\chi^2 = \frac{(21-12)^2}{12}+\frac{(16-12)^2}{12}+\frac{(10-12)^2}{12}+\frac{(8-12)^2}{12}+\frac{(5-12)^2}{12}=13.833

Now we can calculate the degrees of freedom for the statistic given by:

df=(catgories-1)=(5-1)=4

And we can calculate the p value given by:

p_v = P(\chi^2_{4} >13.833)=0.00785

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(13.833,4,TRUE)"

Since the p value is lower than the significance level we can reject the null hypothesis at 5% of significance, and we can conclude that the  drowsiness are NOT equally distributed among office workers .

7 0
4 years ago
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