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Zinaida [17]
3 years ago
8

Ball A is thrown in a horizontal x-direction from a certain height. Ball B is dropped at the same time and from the same height.

Which of the following statements is true about Balls A and B? (Neglect Air Resistance}
Physics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

Answer:

Both balls hit the ground simultaneously

Explanation:

Let´s call b₁  ( the ball dropped ) the equation for a free fall movement is, tacking as the origin of coordinates  the level from which it was dropped

V = g*t  ( since V₀ initial velocity is 0 )

In the case of projectile movement the equation for Vx and Vy (these speeds are independent)

are:

Vx = V₀x      (constant)    and Vy = Voy + g*t  

Vy = V₀ * sin 0⁰ + g*t      Vy = 0 + g*t

As we can see V is the same in both cases then the balls hit the ground simultaneously

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When the input voltages of a difference amplifier are 5.1 v and 6.4 v, the output voltage is 64.7 v. The inputs are changed to 4
daser333 [38]

Answer:

a) Differential mode gain = 48

b) Common mode gain = 0.4

c) CMRR = 120

Explanation:

The output of a difference amplifier is related to the input by the equation:

V_{0} = A_{1} V_{1} + A_{2} V_{2} \\

When V₁ = 6.4 V, V₂ = 5.1 V and V₀ = 64.7 V, the equation becomes

6.4 A₁ + 5.1 A₂ = 64.7.....................(1)

When V₁ = 5.6 V, V₂ = 4.9 V and V₀ = 35.7 V, the equation becomes

5.6 A₁ + 4.9 A₂ = 35.7.....................(2)

Multiply equation (1) by 5.6  and (2) by 6.4

35.84 A₁ + 28.56A₂ = 362.32.....................(3)

35.84 A₁ + 31.36 A₂ = 228.48....................................(4)

Subtract equation (3) from (4)

2.8 A₂ = -133.84

A₂ = -133.84/2.8

A₂ = -47.8

Put the value of  A₂ into equation (1)

6.4 A₁ + 5.1 (-47.8) = 64.7

6.4 A₁ = 64.7 + 243.78

A₁ = 308.48/6.4

A₁ = 48.2

a) Common mode gain = A₁ + A₂ = 48.2 + (-47.8)

Common mode gain = 0.4

b) Differential mode gain = (A₁ -A₂)/2

Differential mode gain = (48.2 - (-47.8))/2

Differential mode gain = 96/2

Differential mode gain = 48

c) Common Mode Rejection Ratio (CMRR)

CMRR = |\frac{Differential Mode Gain}{Common Mode Gain} |

CMRR = |\frac{48}{0.4} |\\CMRR = 120

4 0
3 years ago
Gravity pulls downward on a rock with a force of 800 N. If you pull upward on the rock with a force of 400 N, what is the total
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The answer is
a. 400 N downward
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A truck starts off 151 miles directly north from the city of Hartville. It travels due east at a speed of 41 miles per hour. Aft
Bess [88]

Answer:

9.51

Explanation:

The distance s is given by:

s(t) = \sqrt{151^2 + (vt)^2}

The change in distance is given by the time derivative of s:

\frac{ds}{dt} = \frac{v^2t}{\sqrt{151^2 + (vt)^2}}

For the time t you solve the equation of distance x for time:

x = vt => t = \frac{x}{v}

Plugging in for t:

\frac{ds}{dt}(t=\frac{x}{v})=\frac{vx }{\sqrt{151^2 + x^2}}=9.51

6 0
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A friend of yours who is traveling the world reports that she recently experienced a day on which the surface wind blew from the
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Answer:

At that time, she was in the southern hemisphere

Explanation:

She is witnessing the southeastern trade breeze because the cloud is passing from east to west and she is also witnessing a storm from the southeast.

Because of the Coriolis effect, which deviates the atmosphere in the left-hand side of the southern hemisphere and generates a southeastern wind, this wind did not blow directly from south to east.

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