Answer:
A skater glides along a circular path. She defines a certain point on the circle as her origin. Later on, she passes through a point at which the distance she has traveled along the path from the origin is smaller than the magnitude of her displacement vector from the origin.
So here in circular motion of the skater we can see that the total path length of the skater is along the arc of the circle while we can say that displacement is defined as the shortest distance between initial and final position of the object.
So it is not possible in any circle that arc-length is less than the chord joining the two points on the circle
As we know that arc length is given as

length of chord is given as

so here


so we have

<span>12-50t=70t, t= 0.1h = 6 minutes.</span>
Answer:
<em>The lighten travels 0.853 miles.</em>
Explanation:
Sound: Sound is a form of wave which is conveyed through an elastic medium from a vibrating body to a listener.
v = 2x/t .......................................... Equation 1
making x the subject of the equation
x = vt/2........................................ Equation 2
Where v = velocity of sound in air, x = distance traveled by the sound, t = time
Given: v = 344 m/s t = 8 s
Substituting into equation 2
x = 344(8)/2
x = 1376 m.
x = 1376×0.00062 miles = 0.853 miles
<em>Thus the lighten travels 0.853 miles.</em>
1. Find the force of friction between the sports car and the station wagon stuck together and the road. The total mass m = 1928kg + 1041kg = 2969kg. The only force in the x-direction is friction: F = μ*N = μ * m * g
2. Find the acceleration due to friction:
F = m*a = μ * m * g => a = μ * g = 0.6 * 9.81
3. Find the time it took the two cars stuck together to slide 12m:
x = 0.5*a*t²
t = sqrt(2*x / a) = sqrt(2 * x / (μ * g) )
4. Find the initial velocity of the two cars:
v = a*t = μ * g * sqrt(2 * x / (μ * g) ) = sqrt( 2 * x * μ * g)
5. Use the initial velocity of the two cars combined to find the velocity of the sports car. Momentum must be conserved:
m₁ mass of sports car
v₁ velocity of sports car before the crash
m₂ mass of station wagon
v₂ velocity of station wagon before the crash = 0
v velocity after the crash
m₁*v₁ + m₂*v₂ = (m₁+m₂) * v = m₁*v₁
v₁ = (m₁+m₂) * v / m₁ = (m₁+m₂) * sqrt( 2 * x * μ * g) / m₁
v₁ = 33.9 m/s
We know, Potential Energy = Force * Height
Here, F = 40 N
h = 5 m
Substitute their values,
U = 40 * 5
U = 200 J
In short, Your Answer would be Option A
Hope this helps!