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2 years ago

A car can move from rest to 35 m/s in 5.0 seconds. It's acceleration is

Physics

1 answer:

lord [1]2 years ago

6 0

Answer:

A) 7.0 m/s²

Explanation:

Acceleration is found by using the formula:

a = Δv/Δt

This means the change in time divided by the time interval will give us the car's acceleration.

Since the car starts from rest, its initial velocity is 0 m/s. Its final velocity is 35 m/s. The time interval for the car to go from 0 to 35 m/s is 5.0 seconds.

a = (v - v₀)/t

Substitute the final and initial velocity into the formula.

a = (35 - 0)/5
a = 35/5
a = 7

The acceleration of the car is A) 7.0 m/s².

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An observer is approaching at stationary source at 17.0 m/s. Assuming the speed of sound is 343 m/s, what is the frequency heard

UNO [17]

Answer:

the frequency heard by the observer is equal to 2677 Hz

Explanation:

given,

velocity of the observer = 17 m/s

speed of the sound = 343 m/s

velocity of the source = 0 m/s

frequency emitted from the source = 2550 Hz

$f = f_0(\dfrac{v-v_0}{v-v_s})$

$f = 2550\times (\dfrac{343+17}{343-0})$

velocity of observer is negative as it is approaching the source. f = 2676.38 Hz ≈ 2677 Hz

hence, the frequency heard by the observer is equal to 2677 Hz

7 0

3 years ago

A roller coaster starts from rest at point a and continues to point b on a frictionless track. what best describes the changes i

saw5 [17]

<span>At first when the car is at the datum point where is no elevation, the kinetic energy increases while the potential energy is zero. As it travel the path and goes upward the kinetic enrgy decreases while the potential energy increases. When it goes down again the kinetic enrgy increases again while the potential energy decreases </span>

3 0

3 years ago

Read 2 more answers

This diagram shows the process that powers stars. This process is called?

viktelen [127]

The process that powers stars is C)fusion

4 0

2 years ago

Read 2 more answers

The rate (in liters per minute) at which water drains from a tank is recorded at half-minute intervals. Use the average of the l

lana [24]

Answer:

see explanation

Explanation:

You are missing the chart with the rates and time to do this, however, I wll do it with a similar exercise here, and you only need to replace the procedure with your data:

See the attached table.

From the left we have:

r = 1/2 (50 + 48 + 46 + 44 + 42 + 40) = 135 L/min

From the right we have:

r = 1/2 (48 + 46 +44 + 42 + 40 + 38) = 129 L/min.

And this should be the correct answer. Watch your chart and replace if it's neccesary.

3 0

3 years ago

A ball with a mass of 170 g which contains 3.80×108 excess electrons is dropped into a vertical shaft with a height of 145 m . A

yaroslaw [1]

Answer:

A. F=6.65*10^{-10}N

B. south - north

Explanation:

A) We use the Lorentz force

F = qv X B

|F| = qvB

to calculate the magnitude of the force we need the speed of the of the ball.

$v_{f}^{2}=v_{0}^{2}+2gy\\v_{f}=\sqrt{0+2(9.8\frac{m}{s^{2}})(145m)}=53.31\frac{m}{s}$

and by replacing in the formula for the magnitude of the force we have (taking into account the excess of electrons)

$F=(3.8*10^{8})(1.602*10^{-19}C)(53.31\frac{m}{s})(0.205T)=6.65*10^{-10}N$

b. south - north (by the rigth hand rule)

I hope this is usefull for you

regards

8 0

3 years ago