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pav-90 [236]
3 years ago
8

A car can move from rest to 35 m/s in 5.0 seconds. It's acceleration is

Physics
1 answer:
lord [1]3 years ago
6 0

Answer:

A) 7.0 m/s²

Explanation:

Acceleration is found by using the formula:

  • a = Δv/Δt

This means the change in time divided by the time interval will give us the car's acceleration.

Since the car starts from rest, its initial velocity is 0 m/s. Its final velocity is 35 m/s. The time interval for the car to go from 0 to 35 m/s is 5.0 seconds.

  • a = (v - v₀)/t

Substitute the final and initial velocity into the formula.

  • a = (35 - 0)/5
  • a = 35/5
  • a = 7

The acceleration of the car is A) 7.0 m/s².

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A horizontal uniform bar of mass 3 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to the
kirill115 [55]

Answer:

T₁ = 2.8125 N

Explanation:

The equilibrium equation of the moments at the point where string 2 is located on the bar is like this:

∑M₂ = 0

M₂ = F*d

Where:

∑M₂  : Algebraic sum of moments in the the point (2) of the bar

M₂ : moment in the point 2 ( N*m)

F  : Force ( N)

d  : Horizontal distance of the force to the point 2 ( N*m

Data

mb = 3 kg : mass of the  bar

mm = 1.5 kg :  mass of the  monkey

L = 3m : lengt of the bar

g = 9.8 m/s²: acceleration due to gravity

Forces acting on the bar

T₁ : Tension in string 1 (vertical upward)

T₂ : Tension in string 2 (vertical upward)

Wb :Weihgt of the bar (vertical downward)

Wm: Weihgt of the monkey  (vertical downward)

Calculation of the weight of the bar (Wb) and of the monkey(Wm)

Wb = m*g = 3 kg*9.8 m/s² = 29.4 N

Wm = m*g = 1.5 kg*9.8 m/s² = 14.7 N

Calculation of the distances  from forces the point 2

d₁₂ = (3-0.6) m = 2.4m  : Distance from T1 to the point 2

db₂ = (3÷2) m = 1.5 m : Distance from Wb to the point 2

dm₂ = (3÷2) m = 1.5 m : Distance from Wm to the point 2

Equilibrium  of moments at the point  2 on the bar

∑M₂ = 0

T₁(d₁₂) - Wb(db₂) - Wm(dm₂) = 0

T₁(2.4) -3*(1.5) - 1.5*(1.5) = 0

T₁(2.4) =3*(1.5) + 1.5*(1.5)

T₁(2.4) =6.75

T₁ = 6.75 / (2.4)

T₁ = 2.8125 N

5 0
3 years ago
A water bath in a physical chemistry lab is 1.55 m long, 0.710 m wide, and 0.570 m deep (high). If it is filled to within 3.55 i
Lesechka [4]

Answer:

528 liter.

Explanation:

Volume of the tank(cuboid) = l*b*h

But volume of the water = l*b*h

Where

l= length of the tank

b = width of the tank

h = the length from the bottom of the tank,

3.55 in to m,

0.09017m

Length of the water in the tank = 0.570 - 0.09017

= 0.47983 m.

Volume = 0.47983*0.710*1.55

= 0.528 m3.

1 m3 = 1000 liter.

0.528 m3 = 0.528*1000

= 528 liter

7 0
3 years ago
Calculate the acceleration using the formula acceleration = (final velocity - initial velocity) / time.
PtichkaEL [24]

Answer:

10 km/hr/s

Explanation:

The acceleration of an object is given by

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time

For the car in this problem:

u = 0

v=60 km/h

t = 6 s

Substituting in the equation,

a=\frac{60 km/h-0}{6s}=10 km/h/s

6 0
3 years ago
Think about lifestyle choices that you make on a daily basis. Choose at least four lifestyle choices which you could change to i
eimsori [14]
A.The four lifestyle choices which I could change are:
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2, The number of hours I sleep.
3. The quantity of junk foods I consume daily and 
4. Cultivation of the habit of spending time alone daily.
B. My days are always very busy, so I do not engage at all in physical exercise. Adding at least a thirty minute of physical exercise to my daily tasks will improve my health considerable. Due to the nature of my day, I usually eat on the move, thus I eat junk foods everyday. Eating healthy and balanced diet will go a long way in improving my health. I sleep for three hours only everyday, from 2 am to 5 am.This is because I have to leave my house very early in the morning and I don't usually get to sleep until 2 am in the morning. Spending more hours sleeping will improve my overall health. I want to start spending at least 30 minutes alone on a daily basis in order to meditate and to reflect over the events of the day. This will be a great boost to my mental health.
4 0
3 years ago
Waves transport
Brilliant_brown [7]

Answer:

d)energy

Explanation:

Waves can transfer energy over distance without moving matter the entire distance. For example, an ocean wave can travel many kilometers without the water itself moving many kilometers. The water moves up and down—a motion known as a disturbance. It is the disturbance that travels in a wave, transferring energy.

5 0
3 years ago
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