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sineoko [7]
3 years ago
14

1. The Royals softball team played 125 games and won 60 of them. What percent of the games did they lose? A. 48% B. 52% C. 65% D

. 75%​
Mathematics
1 answer:
Sauron [17]3 years ago
3 0

Answer:

52% or B.

Step-by-step explanation:

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The cheerleaders are selling tickets to a pasta dinner to raise money for new competition outfits. They plan to charge $6 per pe
kow [346]

Answer:

22 and a half ticket sold here will result in no profit situation for cheerleaders.

Step-by-step explanation:

The charge per person = $6

The total cost for dinner = $135

If cheerleaders do not make any profit , then

{ If the money earned from tickets  = The money Spent} ⇒ NO PROFIT

Now, charge per person = $6

So, number of person needed to earn a total of $135

n = \frac{\textrm{The total money needed}}{\textrm{Charge per person}}

n = \frac{135}{6} = 22.5

So, 22 and a half ticket sold here will result in no profit situation for cheerleaders.

If they sell 23 tickets, they will have a profit of $3

And if they sell 22 tickets, they will be short by $3.

5 0
3 years ago
Please answer both of these and show or tell me all your work
horrorfan [7]

Answer:

5. 1:6 2/5

6. 1:5

Step-by-step explanation:

5. each time in the table you multiply H by 6 2/5 ex.

column 4 , 100x6=600, 2/5 of 100 = 40 and the total is 640, so the contant of proprtionality is 6 2/5

6. in the table there is a point on 2:10 and can be simplified to 1:5 so for every minute 5 gallons of water will be used

hope this helps sorry if this inst what your looking for have a blessed day :)

8 0
3 years ago
Marcy played the piano for 45 minutes.She stopped playing at 4:15 P.M.At what time did she start playing the piano
musickatia [10]
15-45=-30
60-30=30
so the answer is 3:30
3 0
3 years ago
Ms. Pickle is a salesperson at Fluffy Dogs. Each week she earns $560 plus a 6.5% of her sales. How much did she earn last week i
katen-ka-za [31]
The anwser would be 1500 your welcome sir or mam
5 0
3 years ago
Which of the following sets is not finite?
Alja [10]
\{x|x\in\mathbb{N}\ \wedge\ n < 10\}=\{0;\ 1;\ 2;\ 3;\ 4;\ 5;\ 6;\ 7;\ 8;\ 9\}-FINITE\\\\\{x|x\in\mathbb{Z}\ \wedge\ 0 < x < 10\}=\{1;\ 2;\ 3;\ 4;\ 5;\ 6;\ 7;\ 8;\ 9\}-FINITE\\\\\{x|x\in\mathbb{Z}\ \wedge\ x < 0\}=\{...;-4;-3;-2;-1\}=\mathbb{Z}^--NOT\ FINITE
8 0
3 years ago
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