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MrRa [10]
3 years ago
13

Please help me with this one

Mathematics
1 answer:
sp2606 [1]3 years ago
5 0
I think 50 oz less
hope it helps

You might be interested in
Given that the population density of Georgia is 170 people per square mile and 10,100,000 people live in Georgia, what is the ar
WINSTONCH [101]

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

Number of people living in Georgia = 10,100,000

Number of people living in per square mile = 170

So, we need to find the area of the state :

So, Area of the state is given by

\frac{\text{Total Population}}{\text{ Number of people per square mile }}\\\\=\frac{10100000}{170}\\\\=59411.76\\\\=59400(\text{ nearest hundred }mi^2)

Hence, Option 'D' is correct.

7 0
3 years ago
Read 2 more answers
An interior automotive supplier places several electrical wires in a harness.Apull test measures the force required to pull spli
oksano4ka [1.4K]

Answer:

a) For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assumin Normal distribution

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical dsitribution

The result is on the figure attached.

b) For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

Step-by-step explanation:

For this case we have the following data:

28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4

The quantile-quantile or q-q plot is a graphical procedure in order to check the validity of a distributional assumption for a data set. We just need to calculate "the theoretically expected value for each data point based on the distribution in question".

If the values are asusted to the assumed distribution, we will see that "the points on the q-q plot will fall approximately on a straight line"

For this case our distribution assumed is normal.

Part a

For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assuming Normal distribution (0,1)

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical distribution

The result is on the figure attached.

Part b

For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

4 0
4 years ago
pe ling needs 2 yards of fabric for a craft project. she has 3 feet already.how many niches of fabric does she still need?
Lostsunrise [7]
Pe Ling would need 36 inches to get 2 yards.
5 0
4 years ago
Read 2 more answers
What is the absolute value equation for this graph?
Delvig [45]

Answer:

y = |x-3| -1

Step-by-step explanation:

The parent function has been shifted right 3 units and down 1 unit. That is f(x)=|x| has been moved to ...

y = f(x -3) -1

y = |x -3| -1 . . . . matches the last choice

6 0
3 years ago
Will mark brainliest if you could explain this to me??
Rasek [7]

Your answer would be 4379 members because at the very beginning you had started off with 4372 members, however as the months go by changes happen. On october, it changed by -10, meaning that 10 students left the school meaning 4372-10=4362 members remaining. Then there's november with -8, so you subtract 8 from your new total 4362-8=4354. Then december comes, and this time it's a positive number, so you have to add 23 to 4354, giving you a new total of 4377. Then there's january, and its back to a negative number so you subtract 12 from 4377, 4377-12=4365. Then february comes and it's a change of a positive number, so you add 3 to the 4365, giving you 4368. And then finally by march, it's another positive number so you add 11 to your total, giving you 4379 students which are now at school. So basically if it's a negative change, subtract from the total, and if it is a positive, add to it. And you have to continue with the total that you got from the previous change that you did. Hope this was helpful

8 0
3 years ago
Read 2 more answers
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