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MrRa [10]
3 years ago
13

Please help me with this one

Mathematics
1 answer:
sp2606 [1]3 years ago
5 0
I think 50 oz less
hope it helps

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The sum of three consecutive terms in an arithmetic sequence is 27, and their product is 585. find the three terms.
sammy [17]
\text{the three consecutive terms in an arithmetic sequence}\\a;\ a+d;\ a+2d\\\\\text{system of equals}\\\\ \left\{\begin{array}{ccc}a+a+d+a+2d=27\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}3a+3d=27&|:3\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}a+d=9&\to d=9-a\\a(a+d)(a+2d)=585\end{array}\right\\
\text{substitute to the second equation}\\\\a(a+9-a)(a+2(9-a))=585\\\\a(9)(a+18-2a)=585\\9a(18-a)=585\ \ \ |:9\\a(18-a)=65\\18a-a^2=65\ \ \ |\text{change the signs}\\a^2-18a=-65\\a^2-2a\cdot9=-65\ \ \ |+9^2\\\underbrace{a^2-2a\cdot9+9^2}_{(a-b)^2=a^2-2ab+b^2}=-65+9^2\\(a-9)^2=16\to a-9\pm\sqrt{16}\\a-9=-4\ \vee\ a-9=4\ \ \ |+9\\a=5\ \vee\ a=13\\\\d=9-5=4\ \vee\ d=9-13=-4
Answer:\ a=5;\ a+d=9; a+2d=13\ vee\ a=13;\ a+d=9;\ a+2d=5

5 0
3 years ago
What are three ratios equal to 4 over 28 .simplify if needed?
SVETLANKA909090 [29]
4/28 = 1/7 when dividing both numerator & denominator by 4 and this would be the simplified fraction.

You could use 1/7 to multiply with others to get other ratios that are equal to 4/28 or you could just use 4/28.

For example:
1/7 = 7/49
or
4/28 = 8/56

6 0
3 years ago
Which is greater 1.831 or 1.381?​
Ivahew [28]

Answer:

1.831

OI JOSUKE

Step-by-step explanation:

4 0
2 years ago
What is 16.748 rounded to nearest hundredths
DIA [1.3K]

Answer:

16.75

Step-by-step explanation:

The number 4 in 16.748 is in the hundredths place.

The number right behind it is 8, which is greater than or equal to 5...

...meaning that it should round up! Not stay the same.

7 0
3 years ago
NO EXPLANATION NEEDED
Degger [83]
10/2 so 5 for 53, 10/4 so 5/2 or 2.5 for 54, and 10/3 or 3.333. For simplicity i divided everything by 10 to remove an extra zero but the answers would still be the same after you reduced
3 0
2 years ago
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