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Marat540 [252]
3 years ago
8

How do I solve 2 2/7 - 1 1/3

Mathematics
2 answers:
sashaice [31]3 years ago
6 0
<em>Let the expression = x</em>

<em>x = [ ( 2 X 7 ) + 2] / 7   -   [ ( 1 X 3 ) + 1 ] / 3</em>
<em>  = [ 14 + 2 ] / 7   -   [ 3 + 1 ] / 3</em>
<em>  = 16 / 7    -   4 / 3</em>
<em>  = ( 48 - 28 ) / 21</em>
<em><u>  = 20 / 21 Answer.. :)</u></em>
olganol [36]3 years ago
5 0
2\frac{2}{7}-1\frac{1}{3}\\\\find\ LCD(\frac{2}{7};\frac{1}{3})\\\\the\ list\ of\ multiples\ of\ 7:\ 0;\ 7;\ 14;\ \fbox{21};\ 28;...\\the\ list\ of\ multiples\ of\ 3:\ 0;\ 3;\ 6;\ 9;\ 12;\ 15;\ 18;\ \fbox{21};\ 24;...\\\\LCD(\frac{2}{7};\ \frac{1}{3})=21\\\\\frac{2}{7}=\frac{2\times3}{7\times3}=\frac{6}{21}\\\frac{1}{3}=\frac{1\times7}{3\times7}=\frac{7}{21}\\-------------------

2\frac{2}{7}-1\frac{1}{3}=2\frac{6}{21}-1\frac{7}{21}=1\frac{21+6}{21}-1\frac{7}{21}=1\frac{27}{21}-1\frac{7}{21}=\boxed{\frac{20}{21}}
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-5.23-9.3= what idk what
kkurt [141]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
What is the effect on the graph of the function f(x) = 2^x when f(x) is replaced with f(x − 3)?
mel-nik [20]

Graph of f(x-3) is compressed by a factor of  \frac{1}{8} horizontally of f(x).

<u>Step-by-step explanation:</u>

We have, the graph of f(x)= 2^{x} , on replacing f(x) by f(x-3) we get:

f(x-3)= 2^{x-3} = \frac{2^{x}}{2^{3}} = \frac{1}{8} 2^{x} = \frac{1}{8} f(x).Below shown are the images for graph of f(x) and f(x-3). Both are functions are exponential , and so having exponential graph but f(x-3) is compressed by a factor of  \frac{1}{8} horizontally . Domain and range of both functions are same i.e. F(x) & f(x-3) domain & range are same , just difference in graph : f(x-3) = \frac{1}{8} f(x).

4 0
3 years ago
Can you form a right triangle with the three lengths given? Why or why not? 4mi, 5mi, 6mi
Vladimir [108]
A right triangle must satisfy this equation: a^2 + b^2 = c^2 

a= shortest length
b=medium length
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a triangle with sides 4,5,6 will satisfy not this equation because:
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16+25 = 41

41 ≠ 36

so the answer is C.

Hope this helps.

-Jabba

6 0
3 years ago
Read 2 more answers
For what value of constant c is the function k(x) continuous at x = 0 if k =
nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x)  is continuous, we take the limit of the parameter as follows:

\mathbf{ \lim_{x \to 0^-} k(x) =  \lim_{x \to 0^+} k(x) =  0 }

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= c }

Provided that:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }

Using l'Hospital's rule:

\mathbf{\implies  \lim_{x \to 0} \ \  \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}=  \lim_{x \to 0}   sec \ x  \ tan \ x = 0}

Therefore:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}=0 }

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

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5 0
2 years ago
Can someone teach me how to answer this? Thanks!
DaniilM [7]

Answer:

\left( fg\right)  \left( x\right)  =2x^3\sqrt[3]{x}\\\\\left( \frac{f}{g} \right)  \left( x\right)  =\frac{2x^{3}}{\sqrt[3]{x} }

Step-by-step explanation:

5 0
2 years ago
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