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3 years ago

Suki named a fraction that was not a multiple of. Which fraction could she have

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

7 0

The correct answer is letter C

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Which is the solution set of this equation? |x – 6| = 15 A. {-9, 21} B. {-15, 15} C. {9, 21} D. {-9, -21} E. {-6, 6}

ale4655 [162]

Answer:

A. -9, 21

Step-by-step explanation:

Use m.a.t.h.w.a.y and you will get the answer!

4 0

3 years ago

Read 2 more answers

Find the product of<br>the sum of<br>3/5 and 1%<br>and

dybincka [34]

Answer:

3/500

Step-by-step explanation:

3/5 x 1%

=> 3/5 x 1/100

=> 3/500

Hope it helps you

8 0

3 years ago

Which number is between 1/2 and 8/9? A- 1/3 B- 7/24 C- 19/24 D- 22/24

irina1246 [14]

1/2=36/72
8/9=64/72

A. 1/3=24/72
B. 7/24=21/72
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D. 22/24=66/24

7 0

4 years ago

Nathan is baking cookies and the recipe calls for 3 2/3 cups of water. He needs to make 1 whole batch and only 1/2 of another ba

klemol [59]

Answer:

Around 5.5 or 5 1/2

Step-by-step explanation:

4 0

3 years ago

The following data represent the age (in weeks) at which 10 randomly selected babies crawled for the first time. 43, 44, 42, 31,

Studentka2010 [4]

Answer:

$42-1.833\frac{6.325}{\sqrt{10}}=38.334$

$42+1.833\frac{6.325}{\sqrt{10}}=45.666$

The 90% confidence interval is given by $38.334 \leq \mu \leq 45.666$

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=42$

The sample deviation calculated $s=6.325$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The Confidence level is 0.90 or 90%, the significance is $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value would be $t_{\alpha/2}=1.833$

Replacing we got:

$42-1.833\frac{6.325}{\sqrt{10}}=38.334$

$42+1.833\frac{6.325}{\sqrt{10}}=45.666$

The 90% confidence interval is given by $38.334 \leq \mu \leq 45.666$

5 0

4 years ago