For

to be continuous at

, we need to have

Note that

means that

, but that

is *approaching* 5. We're told that for

, we have

We can write

and the limit would be

and so

is discontinuous.
(x + 4) (x + 2)
=x^2 +2x + 4x + 8
=x^2 + 6x + 8
the other factor is (x + 2)
Answer:
u = 4
Step-by-step explanation:
Divide by 16 on both sides. [Division Property of Equality]
64/16 = 16u/16
u = 4
==================================================================<em>Hope I Helped, Feel free to ask any questions to clarify :)
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<em> -Aadi x</em>
What kind of operation is this ? it just says x and a nine.