3 years ago

Solve for x: 8^x = (2^7)(4^9).

Mathematics

2 answers:

8_murik_8 [283]3 years ago

7 0

Answer:

C. x = 25/3

Step-by-step explanation:

maksim [4K]3 years ago

5 0

Answer:

C. X= 25/3

Step-by-step explanation:

Exact form: 25/3

Decimal form: 8.3

Mixed number form: 8 1/3

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Answer:

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Step-by-step explanation:

The given equation is

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Differentiate with respect to t.

$4x^3\frac{dx}{dt}=8(5y^4)\frac{dy}{dt}-0$ $[\because \frac{d}{dx}x^n=nx^{n-1},\frac{d}{dx}C=0]$

$4x^3\frac{dx}{dt}=40y^4\frac{dy}{dt}$

It is given that y=2 and dy/dt=1, substitute these values in the above equation.

$4x^3\frac{dx}{dt}=40(2)^4(1)$

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Divide both sides by 4x³.

$\frac{dx}{dt}=\frac{640}{4x^3}$

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Therefore the value of $\frac{dx}{dt}$ is $\frac{160}{x^3}$ .

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3 years ago

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Step-by-step explanation:

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