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alexira [117]
3 years ago
6

Write an equation that you could use to solve for X.

Mathematics
2 answers:
mr_godi [17]3 years ago
7 0

<em>THE</em><em> </em><em>CORRECT</em><em> </em><em>EQUATION</em><em> </em><em>IS</em><em>.</em><em>.</em>

<em>(</em><em>8</em><em>X</em><em>+</em><em>3</em><em>)</em><em>°</em><em>=</em><em>(</em><em>7</em><em>X</em><em>+</em><em>1</em><em>2</em><em>)</em><em>°</em>

<em>[</em><em>BEING</em><em> </em><em>VERTICALLY</em><em> </em><em>OPPOSITE</em><em> </em><em>ANGLES</em><em> </em><em>ARE</em><em> </em><em>ALWAYS</em><em> </em><em>EQUAL</em><em> </em><em>]</em>

HOPE THIS HELPS YOU...

oee [108]3 years ago
4 0

Answer:

8x + 3 = 7x + 12

8x -7x= 12-3

x=9

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The line y = x + 3 has slope 1, so we look for points on the curve where the tangent line, whose slope is dy/dx, is equal to 1.

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Take the derivative of both sides with respect to x, assuming y = y(x) :

2y dy/dx = 1

dy/dx = 1/(2y)

Solve for y when dy/dx = 1 :

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y = 1/2

When y = 1/2, we have x = y² = (1/2)² = 1/4. However, for the given line, when y = 1/2, we have x = y - 3 = 1/2 - 3 = -5/2.

This means the line y = x + 3 is not a tangent to the curve y² = x. In fact, the line never even touches y² = x :

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has no real solution for y.

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