All categories

3 years ago

? Help me plzzz correct answer gets brainliest

Mathematics

2 answers:

natita [175]3 years ago

6 0

Answer:

Step-by-step explanation:

im s0rry im n0t sure

BigorU [14]3 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

Uhm is this a function?

velikii [3]

Yea because every input has only one output

8 0

2 years ago

Read 2 more answers

What is (x - 4y) (-3x - 2y) = ?

Artemon [7]

The answer is -3x^2+10xy+8y^2

3 0

3 years ago

A machine that produces a major part for an airplane engine is monitored closely. In the past, 10% of the parts produced would b

nata0808 [166]

Answer:

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$p = 0.1$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is

We need a sample size of at least n, in which n is found M = 0.04.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.1*0.9}{n}}$

$0.04\sqrt{n} = 0.588$

$\sqrt{n} = \frac{0.588}{0.04}$

$\sqrt{n} = 14.7$

$(\sqrt{n})^{2} = (14.7)^{2}$

$n = 216$

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

7 0

3 years ago

The number of students at Lala High School is 64 less than 3 times the number of students at Banana High School. Which expressio

dangina [55]

Answer:

3s - 64

Step-by-step explanation:

7 0

3 years ago

The probability of being a universal donor is 6% (O-negative-blood type). Suppose that 6 people come to a blood drive.' a) What

Tcecarenko [31]

Answer:

$Mean = 0.36$

$SD = 0.5817$

$P(x=3) = 0.003588$

Step-by-step explanation:

Given

Let

A = Event of being a universal donor.

So:

$P(A) = 0.06$

$n = 6$

Solving (a): Mean and Standard deviation.

The mean is:

$Mean = np$

$Mean = 6 * 0.06$

$Mean = 0.36$

The standard deviation is:

$SD = \sqrt{np(1-p)}$

$SD = \sqrt{6*0.06*(1-0.06)}$

$SD = \sqrt{0.3384}$

$SD = 0.5817$

Solving (b): P(x = 3)

The event is a binomial event an dthe probability is calculated as:

$P(x) = ^nC_x * p^x * (1-p)^{n-x}$

So, we have:

$P(x=3) = ^6C_3 * 0.06^3 * (1-0.06)^{6-3}$

$P(x=3) = ^6C_3 * 0.06^3 * (1-0.06)^3$

$P(x=3) = 20 * 0.06^3 * (1-0.06)^3$

$P(x=3) = 0.003588$

7 0

2 years ago