Answer:
The answer to the question is
The actual duration of the trip is 8/9 times the normal duration or the bus arrived 1/9 times earlier than it would have at a constant speed of v kph
Step-by-step explanation:
Speed of bus in the first third distance = v kph
Speed of bus for the remaining two thirds = 1.2 v kph
To solve the question, we note that speed = distance/time
therefore time = distance/speed
Let the distance of the destination be D, then
Normal duration at speed v = D/v
Actual duration (D/3)÷v + (2D/3)÷(1.2v) ⇒ (1.2*D/3 + 2D/3)1.2v
=
= (8/9)×D/v
Therefore the actual duration is 8/9 times the normal duration
<span>We have this equation:
</span>

and we need to find the value of x.
First of all, we multiply the whole equation for 1/2, so our goal is to isolate x, therefore:
Next step we must do is to apply <span>logarithms:
</span>

Next, we have to apply identities and then to solve the equation:




Finally, we have the value of x which was our goal. This is the answer for the question above:
Answer: the graph is correct.
Step-by-step explanation:
Answer:
Step-by-step explanation:
The posssible factors are
x^2 + 4x - 32
(x+8)(x-4)
x^2+ 14x - 32
(x+16)(x-2)
(x+32)(x-1)
x^2+31x-32