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3 years ago

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I have 8 markers. (Marker colors are brown, purple, red, orange, yellow, blue, green, black) I will close my eyes and whatever 2

markers I pick, I will draw my whole picture with those. After closing my eyes, I stick my hand in the pile, and pull out black! A versatile option indeed. I'm thrilled.
What is the probability that my picture will be black and a primary color(red, blue, or yellow)? Write answer as a fraction with this fraction bar /

1 answer:

Elina [12.6K]3 years ago

3 0

Answer:

I am not very sure but I think the probability will be 1/3 because there are only 3 primary colors and 4 secondary colors

Step-by-step explanation:

Hope this helped :)

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Please help will mark brainliest (random answers will be reported)

maxonik [38]

I believe its B
i hope this helps :)

3 0

3 years ago

Read 2 more answers

Jaxon and Lucius were selling lemonade. Jaxon and Lucius have a difference of 5 cups sold. Jaxon was selling his for $6 a cup an

dimaraw [331]

Answer:

the points are (35,30) you may need to search a graph online i used desmos

Step-by-step explanation:

1. x= Jacksons Cups y= Lucius Cups2. x - y= 5 6x + 3y = 300Substitution: 6 (y+5) + 3y = 300 6y + 30 + 3y = 300 9y = 270 dived both by 9 y=30 Sub y for other equation x - 30 = 5 add 30 to both sides x = 35 Answer: (35, 30) Graphing: x- y = 56x+ 3y = 300solve both for y y = x-5 6x + 3y = 300minus 6x from both sides the points are in y = mx + b y= 1x -5 y= -2x + 100 I will also leave the ss of the graph in the comments if you cannot see it My labels for the x-axis is Jacksons cups and y Is luscious cups. Elimination:x - y = 5 6x + 3y = 300 First I manipulated the equations by the following - 6 (x - y = 5 ) 1(6x + 3y = 300 ) -6x + 6y = -30 6x + 3y = 300 The 6 x's cancel and add the y's and real numbers together 9y = 270 dived both by 9 y= 30 Sub y for other equation x - 30 = 6 add 30 to both sides x= 30 The points are (35, 30) The solution is (35,30)They represent how many cups they sold. 35 is Jackson cups and 30 is Lucious's cups

7 0

3 years ago

Let f(x) = 1/x^2 (a) Use the definition of the derivatve to find f'(x). (b) Find the equation of the tangent line at x=2

Verdich [7]

Answer:

(a) $f'(x)=-\frac{2}{x^3}$

(b) $y=-0.25x+0.75$

Step-by-step explanation:

The given function is

$f(x)=\frac{1}{x^2}$ .... (1)

According to the first principle of the derivative,

$f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{x^2-x^2-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-h(2x+h)}{hx^2(x+h)^2}$

Cancel out common factors.

$f'(x)=lim_{h\rightarrow 0}\frac{-(2x+h)}{x^2(x+h)^2}$

By applying limit, we get

$f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}$

$f'(x)=\frac{-2x)}{x^4}$

$f'(x)=\frac{-2)}{x^3}$ .... (2)

Therefore $f'(x)=-\frac{2}{x^3}$ .

(b)

Put x=2, to find the y-coordinate of point of tangency.

$f(x)=\frac{1}{2^2}=\frac{1}{4}=0.25$

The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

$m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}$

Substitute x=2 in equation 2.

$f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25$

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

$y-y_1=m(x-x_1)$

$y-0.25=-0.25(x-2)$

$y-0.25=-0.25x+0.5$

$y=-0.25x+0.5+0.25$

$y=-0.25x+0.75$

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

5 0

3 years ago

2m-8-m+10 solve it.

Olin [163]

Answer:

m+2

Step-by-step explanation:

Collect like terms

m-8+10

Calculate the term

x+2

Hope this helpsʕ•ᴥ•ʔ

4 0

3 years ago

What does - 12/s - 5 - 9w use s =4 and w = 3 equal

qwelly [4]

Your answer would be -35.

5 0

3 years ago