Answer:<em>IDK</em>
Step-by-step explanation:i don' t know
Answer:
English please
Step-by-step explanation:
Answer:
a) there is s such that <u>r>s</u> and s is <u>positive</u>
b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r
Step-by-step explanation:
a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.
b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.
Answer:
1/10
13/100
4/5
12/25
3/10
63/100
3/5
51/200
2/9
5/11
To prove the last 2 recurring ones:
0.222222... = x
10x = 10 * 0.22222... = 2.222222....
Notice how the decimal part of 10x is the same as for x:
10x - x = 2.2222222... - 0.222222... = 2
10x - x = 9x = 2
x = 2/9
Same procedure for the other one but times by 100 instead:
x = 0.454545...
100x = 45.454545...
100x - x = 45.454545... - 0.454545... = 45
100x - x = 99x = 45
x = 45/99 = 5/11
Answer:
See Explanation
Step-by-step explanation:
