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Leviafan [203]
3 years ago
11

What is the value of 7x squared + 2x when x = 3

Mathematics
1 answer:
Vadim26 [7]3 years ago
7 0

Answer:

The value of equation is 69   at x=3

Step-by-step explanation:

Given Equation:

        7x^2+2x

We have to find the value of the expression at x=3

Putting the value of 'x' in the given equation.

                 =7(3)^2+2(3)\\

                 =(7*9)+6\\63+6\\69

The value of the above expression at x=3 is 69.

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One day, a sprinter runs the 100 m dash 24 times, for a total distance of 24 00 m. how many kilometers did the sprinter run?
tigry1 [53]

The total distance that was covered by the sprinter in Kilometers is:

  • 2.4 Km

<h3>How much is the total distance covered?</h3>

To obtain the total distance covered by the sprinter, we need to first realize that 1 Km is equal to 1000 meters. That said, the question above requires us to change 2400 meters to kilometers.

Thus we will have:

2400 Meters * 1 km / 1000 meters

= 2.4 km

So, the total distance covered by the sprinter in kilometers is 2.4

Learn more about meter conversions here:

brainly.com/question/26259781

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4 0
1 year ago
Need help with this please I am in math class
Tpy6a [65]

Answer:

256.8

Step-by-step explanation:

the tenths place is the first number after the decimal.

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3 years ago
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ExtremeBDS [4]

Answer:

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Step-by-step explanation:

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3 years ago
7-4i divided by <br> 2+i <br> how to solve it?
cupoosta [38]
\cfrac{7-4i}{2+i}\\\\ = \cfrac{(7-4i)(2-i)}{(2+i)(2-i)} \\\\ =\cfrac{14-7i-8i-4}{4+1} \\\\= \cfrac{10-15i}{5} \\\\= \cfrac{5(2-3i)}{5} \\\\=2-3i
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What is the exact value of arccos(−2√2) ?
Strike441 [17]

Answer:

See explanation

Step-by-step explanation:

The range of the cosine function is -1\le \cos x\le 1

Therefore arc \cos (-2\sqrt{2}) is not defined.

Assuming your question is rather arc \cos (-\frac{\sqrt{2}}{2})

Then arc \cos (-\frac{\sqrt{2}}{2})=\pi-arc \cos (\frac{\sqrt{2}}{2})  in the second quadrant.

arc \cos (-\frac{\sqrt{2}}{2})=\pi-\frac{\pi}{4}

arc \cos (-\frac{\sqrt{2}}{2})=\frac{3\pi}{4}

4 0
3 years ago
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