Simplify 15 – 3(6

Hannah was asked to make d the subject of the formula<br> d-7=4d+3/e<br> Finish her question.

tigry1 [53]

Answer:

$d = \frac{-1}{e} - \frac{7}{3}$

Step-by-step explanation:

In order to make d the subject of the formula, you need to isolate it.

- You started with d-7 = 4d + 3/e

- Move 4d to the left side by subtracting 4d from both sides to cancel it from the right so you have...

d - 7 = 4d + 3/e This will leave you left with -3d - 7 = 3/e

-4d -4d

- Then move over the -7 by adding 7 to both sides...

-3d - 7 = 3/e This will leave you left with -3d = 3/e + 7

+7 +7

- Finally to get d by itself divide both sides of the equation by -3 and you'll be left with...

$d = \frac{3}{-3e} -\frac{7}{3}$

- You can cancel out the 3 in the -3/3e and make it -1/e so your final answer will be

$d = \frac{-1}{e} - \frac{7}{3}$

5 0

3 years ago

Chelsea needs to take a taxi home and lives 7 miles away. The taxi company charges $4 plus $1.50 per mile. How much will she pay

Elza [17]

$14.50 because your equation would be 4+1.50(7)=$14.50.

6 0

2 years ago

May I please get some help?

Vladimir79 [104]

I think its 80 m3 or either 18 m3

3 0

2 years ago

Read 2 more answers

LOTS OF POINTS GIVING BRAINLIEST I NEED HELP PLEASEE

Sidana [21]

Answer:

Segment EF: y = -x + 8

Segment BC: y = -x + 2

Step-by-step explanation:

Given the two similar right triangles, ΔABC and ΔDEF, for which we must determine the slope-intercept form of the side of ΔDEF that is parallel to segment BC.

Upon observing the given diagram, we can infer the following corresponding sides:

$\displaystyle\mathsf{\overline{BC}\:\: and\:\:\overline{EF}}$

$\displaystyle\mathsf{\overline{BA}\:\: and\:\:\overline{ED}}$

$\displaystyle\mathsf{\overline{AC}\:\: and\:\:\overline{DF}}$

We must determine the slope of segment BC from ΔABC, which corresponds to segment EF from ΔDEF.

<h2>Slope of Segment BC:</h2>

In order to solve for the slope of segment BC, we can use the following slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}} }$

Use the following coordinates from the given diagram:

Point B: (x₁, y₁) = (-2, 4)

Point C: (x₂, y₂) = ( 1, 1 )

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{1\:-\:4}{1\:-\:(-2)}\:=\:\frac{-3}{1\:+\:2}\:=\:\frac{-3}{3}\:=\:-1}$

<h2>Slope of Segment EF:</h2>

Similar to how we determined the slope of segment BC, we will use the coordinates of points E and F from ΔDEF to find its slope:

Point E: (x₁, y₁) = (4, 4)

Point F: (x₂, y₂) = (6, 2)

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{2\:-\:4}{6\:-\:4}\:=\:\frac{-2}{2}\:=\:-1}$

Our calculations show that segment BC and EF have the same slope of -1. In geometry, we know that two nonvertical lines are <u>parallel</u> if and only if they have the same slope.

Since segments BC and EF have the same slope, then it means that $\displaystyle\mathsf{\overline{BC}\:\: | |\:\:\overline{EF}}$ .

<h2>Slope-intercept form:</h2><h3><u>Segment BC:</u></h3>

The <u>y-intercept</u> is the point on the graph where it crosses the y-axis. Thus, it is the value of "y" when x = 0.

Using the slope of segment BC, m = -1, and the coordinates of point C, (1, 1), substitute these values into the <u>slope-intercept form</u> (y = mx + b) to solve for the y-intercept, <em>b. </em>

y = mx + b

1 = -1( 1 ) + b

1 = -1 + b

Add 1 to both sides to isolate b:

1 + 1 = -1 + 1 + b

2 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 2.

Therefore, the linear equation in <u>slope-intercept form of segment BC</u> is:

⇒ y = -x + 2.

<h3><u /></h3><h3><u>Segment EF:</u></h3>

Using the slope of segment EF, <em>m</em> = -1, and the coordinates of point E, (4, 4), substitute these values into the <u>slope-intercept form</u> to solve for the y-intercept, <em>b. </em>

y = mx + b

4 = -1( 4 ) + b

4 = -4 + b

Add 4 to both sides to isolate b:

4 + 4 = -4 + 4 + b

8 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 8.

Therefore, the linear equation in <u>slope-intercept form of segment EF</u> is:

⇒ y = -x + 8.

8 0

2 years ago

HELP PLZ! I do not understand this!!

neonofarm [45]

PART 1
If I have graph f(x) then graph f(x + 1/3) would translate the graph 1/3 to the left.

For example, I have f(x) = x².Then
f(x + 1/3) = (x + 1/3)²

I draw the graph of f(x) = x² and the graph of f(x) = (x + 1/3)² on cartesian plane to know what's the difference between them.

PART 2
If I have graph f(x) then graph f(x) + 1/3 would translate the graph 1/3 upper.

For example, I have f(x) = x².Then
f(x) + 1/3 = x² + 1/3

I draw the graph of f(x) = x² and the graph of f(x) = x² + 1/3 on cartesian plane to know what's the difference between them.

SUMMARY
f(x+1/3) ⇒⇒ <span>f(x) is translated 1/3 units left.
f(x) + 1/3 </span>⇒⇒ <span>f(x) is translated 1/3 units up.</span>

3 0

3 years ago

Read 2 more answers

Simplify 15 – 3(6 – 4).