The distance between points A (3, -5) and A' (2, -3) is 2.4 units.
Given that,
The points A (3, -5) and A' (2, -3).
We have to determine,
The distance between point A and A'.
According to the question,
The distance between two points is determined by using the distance formula.

Then,
The distance between points A (3, -5) and A' (2, -3) is,

Hence, The distance between points A (3, -5) and A' (2, -3) is 2.4 units.
For more details refer to the link given below.
brainly.com/question/8069952