What is the initial value for the function in the example<br> problem? What is the rate of change?

PLEASE HELP NEED THIS TO PASS

yaroslaw [1]

The solutions to f(x) = 64 is x = 7 and x = –7.

Solution:

Given data:

$$f(x)=x^{2}+15$ – – – – (1)

$f(x)=64$ – – – – (2)

To find the solutions to f(x) = 64.

Equate equation (1) and (2), we get

$x^2+15=64$

Subtract 15 from both sides of the equation.

$x^2+15-15=64-15$

$x^2=49$

$x^2=7^2$

Taking square root on both sides of the equation, we get

x = ±7

The solutions to f(x) = 64 is x = 7 and x = –7.

5 0

3 years ago

1/4x – 2 = 3/8 Please show an equation and work. :)

Julli [10]

1/4x - 2 = 3/8

First, to start solving this, we can rearrange our fraction. Let's take 1/4x and change it to x/4. Why? Well, a variable can also be considered as the number 1.
$\frac{x}{4} - 2 = \frac{3}{8}$

Second, now we can continue solving for our variable (x). Let's add 2 to each side.
$\frac{x}{4} = \frac{3}{8} + 2$

Third, let's simplify 3/8 + 2. (3/8 + 2 = 2.375 =19/8)
$\frac{x}{4} = \frac{19}{8}$

Fourth, continue trying to get the variable by itself. Multiply each side by 4.
$x = \frac{19}{8} \times 4$

Fifth, let's simplify 19/8 × 4. This is simple. Leave the denominator be and just do 19 × 4, which equals 76.
$x = \frac{76}{8}$

Sixth, our final step is to simplify our fraction. To do so, we will need to list the factors of the numerator and denominator and find the greatest common factor (GCF).

Factors of 76: 1, 2, 4, 19, 38, 76
Factors of 8: 1, 2, 4, 8

Since 4 is our first common factor, it is considered our GCF.

Seventh, now let's divide. Divide both the numerator and denominator by the GCF (4) to create our new simplified fraction.
$76 \div 4 = 19 \\ 8 \div 4 = 2$

Answer in fraction form: $\fbox {x = 19/2}$
Answer in decimal form: $\fbox {x = 9.5}$

8 0

3 years ago

how many such tests would it take for the probability of committing at least one type i error to be at least 0.7? (round your an

drek231 [11]

The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .

In the question ,

it is given that ,

the probability of committing at least , type I error is = 0.7

we have to find the number of tests ,

let the number of test be n ,

the above mentioned situation can be written as

1 - P(no type I error is committed) ≥ P(at least type I error is committed)

which is written as ,

1 - (1 - 0.01)ⁿ ≥ 0.7

-(0.99)ⁿ ≥ 0.7 - 1

(0.99)ⁿ ≤ 0.3

On further simplification ,

we get ,

n ≈ 118 .

Therefore , the number of tests are 118 .

Learn more about Error here

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4 0

1 year ago

A doctor wants to estimate the mean HDL cholesterol of all 20- to 29-year-old females. The number of subjects needed to estima

Ludmilka [50]

Answer:

$n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65$

So the answer for this case would be n=65 rounded up to the nearest integer

And the sample size would decrease by 160-65=95 subjects

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

ME represent the margin of error

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

2) Solution to the problem

Since the new Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that $z_{\alpha/2}=1.64$

Assuming that the deviation is known we can express the margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =\pm 3 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

Replacing into formula (b) we got:

$n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65$

So the answer for this case would be n=65 rounded up to the nearest integer

And the sample size would decrease by 160-65=95 subjects

8 0

3 years ago

What is 10×10×10+56÷25+50

OleMash [197]

What I would do is break up into part. First do 10*10*10 which is 1,000. Then add 56 and 50 which is 106. after you do that and get 1,106 divded it by 25 which is 42.54. Hope I helped.

8 0

3 years ago

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What is the initial value for the function in the example problem? What is the rate of change?