Hey I need help on a question real fast the question is if three equals B times seven then seven times be equals what

I am doing tessellations I need help what does this look like

Naily [24]

I can’t do it rn so just dm me later

7 0

4 years ago

Find intercepts of: 3x-3y+9=0 <br> X-intercept as a ordered pair<br> Y-intercept as a ordered pairr

ahrayia [7]

3x - 3y + 9 = 0

The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates of (0, b). It is also the value of y when x = 0.

To solve for the y-intercept, set x = 0:

3(0) - 3y + 9 = 0
3(0) - 3y + 9 = 0

Subtract 9 from both sides:
- 3y + 9 - 9 = 0 - 9
- 3y = -9
Divide both sides by -3 to solve for y:

-3y/-3 = -9/-3
y = 3

Therefore, the y-intercept is (0, 3).

The x-intercept is the point on the graph where it crosses the x-axis, and has coordinates of (a, 0). It is also the value of x when y = 0.

To solve for the x-intercept, set y = 0:

3x - 3(0)+ 9 = 0
3x -0 + 9 = 0

Subtract 9 from both sides:
3x + 9 - 9 = 0 - 9
3x = -9

Divide both sides by 3 to solve for x:

3x/3 = -9/3
x = -3

Therefore, the x-intercept is (-3,0).

The correct answers are:
Y-intercept = (0, 3)
X-intercept = (-3, 0)

7 0

3 years ago

Lesson 9: When Are They the Same?

marysya [2.9K]

Answer:

The number of pages that will make the cost of printing equal for both options is 500

Step-by-step explanation:

Please, kindly see the attached file for explanation

8 0

3 years ago

If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$

6 0

3 years ago

if i have 19 friends they each want 3 slices of cake i have 38 slices how do i divide and get a simple remainder.

Salsk061 [2.6K]

38 divided by 19 than multiply by 3

3 0

3 years ago