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Iteru [2.4K]
3 years ago
13

Hey I need help on a question real fast the question is if three equals B times seven then seven times be equals what

Mathematics
1 answer:
bonufazy [111]3 years ago
3 0

Answer would be 14b.

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What is the solution for x in the equation?<br> 1/2-x+3/2=x-4
kirill115 [55]
It would be the thing where you move the x’s to one side and do the rest of the working out from there
7 0
4 years ago
Based on a​ poll, 67​% of Internet users are more careful about personal information when using a public​ Wi-Fi hotspot. What is
daser333 [38]

Answer:

The required probability is 0.988.

Step-by-step explanation:

Consider the provided information.

Based on a​ poll, 67​% of Internet users are more careful about personal information when using a public​ Wi-Fi hotspot.

That means the probability of more careful is 0.67

The probability of not careful is: 1-0.67 = 0.33

We have selected four random Internet​ users. we need to find the probability that at least one is more careful about personal information.

P(At least one careful) = 1 - P(None of them careful)

P(At least one careful) = 1 - (0.33×0.33×0.33×0.33)

P(At least one careful) = 1 - 0.012

P(At least one careful) = 0.988

Hence, the required probability is 0.988.

The result may be higher because of the convenience bias in retrieving the sample. Because the survey subjects volunteered to​ respond not random.

3 0
4 years ago
Need help ASAP what is 50÷2​
icang [17]
The answer would be 25 because 25 times 2 is 50
5 0
3 years ago
Read 2 more answers
1. A cheetah can run at a top velocity of 31 m/s and has a mass of 47 kg. What is the cheetahs kenetic energy?
Naily [24]

Answer:

1. 22583.5 J

2. 1248 kg

3. 78.09 m/s

Step-by-step explanation:

The formula for kinetic energy is ;

K.E = 1/2* m * v²

Where m is the mass and v is the velocity

1.

K.E = 1/2 * m*v²

K.E = 1/2 * 47 * 31²

K.E = 22583.5 J

2.

Velocity = 9.78 m/s.

Kinetic energy = 60,800 J

To get mass, apply the formula as;

K.E = 1/2 * m*v²

60,800 = 1/2 * m * 9.78²

60800 = 48.70845 m

60800/48.70845 = m

1248 = m

Mass = 1248 kg

3.

K.E = 143.3 J

Mass = 0.047 kg

Apply the formula;

K.E = 1/2 * m*v²

143.3 = 1/2 * 0.047 * v²

143.3 = 0.0235 v²

143.3/0.0235 = v²

6097.87 = v²

v = √6097.87

v= 78.09 m/s

4 0
3 years ago
Suppose that the speeds of cars travelling on California freeways are normally distributed with a mean of miles/hour. The highwa
Readme [11.4K]

Answer:

the standard deviation of the speeds of cars travelling on California freeways is 6.0 miles per hour

Step-by-step explanation:

The computation of the standard deviation of the speeds of cars is shown below;

The z score for the top 1% is 2.326

So,

= (75 - 61) ÷ standard deviation = 2.326

Standard deviation is

= 14 ÷ 2.326

= 6.0 miles per hour

Hence, the standard deviation of the speeds of cars travelling on California freeways is 6.0 miles per hour

4 0
3 years ago
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