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stich3 [128]
2 years ago
11

2. A bus drove 8 meters East, then turned to drive 8 meters North, then 2 meters

Physics
1 answer:
Sphinxa [80]2 years ago
3 0

Answer:

Long question good luck:)

Explanation:

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Where were the girls heading when the car broke down?<br> in the movie *hidden figures*
Ilia_Sergeevich [38]

Explanation:

Katherine Johnson, NASA Mathematician Featured in 'Hidden Figures,' Dies at 101

Feb 25, 2020 — Their story was told in the 2016 Hollywood film “Hidden Figures,” based on Margot Lee Shetterly's nonfiction book of the same title , ...

5 0
3 years ago
When two or more capacitors are connected in series across a potential difference:
34kurt

Answer:

A) and B) are correct.

Explanation:

Let's take a look at the attached picture. Now

The total voltage across both capacitors is the same as the sum of the voltage from each device, that statement is true for any electrical device connected in series. So a) is TRUE

The equivalent capacitance is going to be: \frac{1}{C_{total}}=\frac{1}{C_1} +\frac{1}{C_2}

And that value can be mathematically proven that is always less than any of the values of each capacitor. So b is TRUE

And through both capacitors flow the same current, but the amount of charge depends on the value of the capacitors, so only could be the same if the capacitors are the same value. Otherwise, don't. C) not always, so FALSE

7 0
3 years ago
Which of the following is equivalent to 2.5 meters
blsea [12.9K]
B is the correct answer for sure bro
5 0
3 years ago
Read 2 more answers
Which symbol is used for an alpha particle? a. β c. γ b. Δ d. α
xenn [34]
It is the very last answer

6 0
3 years ago
What must be the pressure difference between the two ends of a 2.6 km section of pipe, 36 cm in diameter, if it is to transport
ad-work [718]

Answer: 1.13(10)^{3} Pa

Explanation:

This problem can be solved by the following equation:

\Delta P=\frac{8 \eta L Q}{\pi r^{4}}

Where:

\Delta P is the pressure difference between the two ends of the pipe

\eta=0.20 Pa.s is the viscosity of oil

L=2.6 km=2600 m is the length of the pipe

Q=900 \frac{cm^{3}}{s} \frac{1 m^{3}}{(100 cm)^{3}}=0.0009 \frac{m^{3}}{s} is the Rate of flow of the fluid

d=36 cm=0.36 m is the diameter of the pipe

r=\frac{d}{2}=0.18 m is the radius of the pipe

Soving for \Delta P:

\Delta P=\frac{8 (0.20 Pa.s)(2600 m)(0.0009 \frac{m^{3}}{s})}{\pi (0.18 m)^{4}}

Finally:

\Delta P=1135.26 Pa \approx 1.13(10)^{3} Pa

7 0
3 years ago
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