Answer:
Average speed will be 30.30 m/sec
Explanation:
We have distance d = 10 km
Time to reach university to home = 20 min
We know that 1 hour = 20 min
So 20 minute ![\frac{20}{60}=0.33hour](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B60%7D%3D0.33hour)
We have to find average speed
We know that distance = speed × time
So ![speed=\frac{distance}{time }=\frac{10}{0.33}=30.30km/hour](https://tex.z-dn.net/?f=speed%3D%5Cfrac%7Bdistance%7D%7Btime%20%7D%3D%5Cfrac%7B10%7D%7B0.33%7D%3D30.30km%2Fhour)
So the average speed will be 30.30 m/sec
It is then converted into a ammonia.
Answer: 2.13 E 4 J
Explanation: Heat absorbed = mass * specific heat capacity * change in temperature
= 0.5 * 387 * (400 - 290) J
= 0.5 * 387 * 110 J = 21285 J = 2.13 E 4 J
Answer:
Where is question 12, we need it to answer this question
Explanation:
Answer:
102900 Joules
Explanation:
Assuming the kinetic energy was zero at the moment of release, you can make the following argument to solve the problem:
The potential energy at full height was mgh. We are told that after 70% of the distance, i.e., mg(0.3h) = 44.1kJ. Since potential energy is linear in altitude h, we get get the full potential energy to be 44.1kJ/0.3. The difference between full potential energy and the one after 70% of the way must equal the gained kinetic energy (neglecting stuff like heat due to friction). So,
44.1kJ/0.3 - 44.1kJ = 0.7*44.1kJ/0.3 = 102.9kJ = Ekinetic
The kinetic energy after 70% of the falling distance was 102.9 kJ.