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Alexeev081 [22]
3 years ago
13

Calculate the position of the center of mass of the following pairs of objects. Use a coordinate system where 0 is at the center

of the more massive object. Give your answer not in meters but as a fraction of the radius as requested. You can find the data you need in the inside of the back cover of your textbook. (a) The Earth and the Moon. Give the answer as a fraction of the earth's radius.
Physics
1 answer:
vlada-n [284]3 years ago
8 0

Answer:

the center of mass is  Rcm = 0.725 R Earth

Explanation:

The concept of center of mass is of great importance in all physics, since on this all external forces of the system can be considered applied, in the collision analysis it gives an ideal reference system for resolution

The equation for the center of mass is

        Rcm = ∑ mi ri / Mt

With Rcm and ri being vector quantities, "m" is body mass and MT total mass

If we write this equation for our system we have

       Rcm = (M1 r1 + M2 r2) / (M1 + M2)

M1 and M2 are the mass of the Earth and the Moon respectively, r1 and r2 are the distances measured from our reference system. As they indicate that we place the most massive reference system we place it on planet Earth.  The data taken a textbook.

       

        M1 = 5.98 10²⁴  Kg

        M2 = 7.36 10²² Kg

       Distance from Earth to the moon on average 3.84 10⁸ m

How the coordinate system is placed on Earth

 

        r1 = 0

        r2 = 3.84 10 8 m

      Rcm = 0 + 7.36 10²²  3.84 10⁸ / (5.98 10²⁴ + 7.36 10²²)

R cm = 2.826 10³¹ / (598 10²² + 7.36 10²²)

Rcm = 2.826 10³¹ / 611.34 10²²

R cm = 4.62 10⁶  m

we are asked to give this distance as a fraction of the radius of the Earth, we divide the two quantities

      R earth = 6.37 10⁶ m

     Fraction = R cm / R Earth

     Fraction = 4.62 10⁶ / 6.37 10⁶

     Fraction = 0.725

In summary the center of mass is

     Rcm = 0.725 R Earth

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Answer:

5 neutrons

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Answer:

Option (3)

Explanation:

Formula used to calculate acceleration is,

F = ma

Where F = force exerted on a mass

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Option (2)

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Option (3)

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Option (4)

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A particle moving along a straight line with constant acceleration has a velocity of 2.35 m/s at t=3.42 s, and a velocity of -8.
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The particle's acceleration is 5.1 m/s²

<h3>What is Acceleration ?</h3>

Acceleration can be defined as the rate at which velocity is changing. It is a vector quantity and it is measured in m/s²

Given that a particle is moving along a straight line with constant acceleration has a velocity of 2.35 m/s at t=3.42 s, and a velocity of -8.72 m/s at t=5.59s

The given parameters are;

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a = (2.35 + 8.72) / (5.59 - 3.42)

a = 11.07 / 2.17

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Therefore, the particle's acceleration is 5.1 m/s²

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A gang of robbers is escaping across city roofs at night. They come to the edge of one building and need to drop down to their g
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Answer:

a) They will hit the ground with a speed of 19.6 m/s.

b) They are at a height of 20 m.

c) It is not a safe jump.

Explanation:

Hi there!

a) The equations of height and velocity in function of time of a free falling body are the following:

h = h0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

h = height of the object at time t.

h0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.8 m/s² considering downward as negative direction).

v = velocity of the object at time t.

Using the equation of velocity, let's find the velocity at which they will hit the ground. The pebble is dropped (initial velocity = 0) and it takes 2 s to reach the ground:

v = v0 + g · t     (v0 = 0)

v = g · t

v = -9.8 m/s² · 2.0 s

v = -19.6 m/s

They will hit the ground with a speed of 19.6 m/s.

b)Now, we have to use the equation of height:

h = h0 + v0 · t + 1/2 · g · t²

If we place the origin of the frame of reference on the ground, we have to find the initial height (h0) knowing that at t = 2.0 s, h = 0 m

0 m = h0 - 1/2 · 9.8 m/s² · (2.0 s)²

h0 = 1/2 · 9.8 m/s² · (2.0 s)²

h0 = 20 m

They are at a height of 20 m.

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