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Alexeev081 [22]
3 years ago
13

Calculate the position of the center of mass of the following pairs of objects. Use a coordinate system where 0 is at the center

of the more massive object. Give your answer not in meters but as a fraction of the radius as requested. You can find the data you need in the inside of the back cover of your textbook. (a) The Earth and the Moon. Give the answer as a fraction of the earth's radius.
Physics
1 answer:
vlada-n [284]3 years ago
8 0

Answer:

the center of mass is  Rcm = 0.725 R Earth

Explanation:

The concept of center of mass is of great importance in all physics, since on this all external forces of the system can be considered applied, in the collision analysis it gives an ideal reference system for resolution

The equation for the center of mass is

        Rcm = ∑ mi ri / Mt

With Rcm and ri being vector quantities, "m" is body mass and MT total mass

If we write this equation for our system we have

       Rcm = (M1 r1 + M2 r2) / (M1 + M2)

M1 and M2 are the mass of the Earth and the Moon respectively, r1 and r2 are the distances measured from our reference system. As they indicate that we place the most massive reference system we place it on planet Earth.  The data taken a textbook.

       

        M1 = 5.98 10²⁴  Kg

        M2 = 7.36 10²² Kg

       Distance from Earth to the moon on average 3.84 10⁸ m

How the coordinate system is placed on Earth

 

        r1 = 0

        r2 = 3.84 10 8 m

      Rcm = 0 + 7.36 10²²  3.84 10⁸ / (5.98 10²⁴ + 7.36 10²²)

R cm = 2.826 10³¹ / (598 10²² + 7.36 10²²)

Rcm = 2.826 10³¹ / 611.34 10²²

R cm = 4.62 10⁶  m

we are asked to give this distance as a fraction of the radius of the Earth, we divide the two quantities

      R earth = 6.37 10⁶ m

     Fraction = R cm / R Earth

     Fraction = 4.62 10⁶ / 6.37 10⁶

     Fraction = 0.725

In summary the center of mass is

     Rcm = 0.725 R Earth

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A person is riding a bicycle, and its wheels have an angular velocity of 10.7 rad/s. Then, the brakes are applied and the bike i
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Answer:

(a) t = 22.9 s

(b) α= - 0.467 rad/s²

Explanation:

The uniformly accelerated circular movement, is a circular path movement in which the angular acceleration is constant.

We apply the equations of circular motion uniformly accelerated :

ωf ²=  ω₀² + 2*α*θ  Formula (1)

ωf= ω₀ + α*t Formula (2)

Where:

θ : angle that the body has rotated in a given time interval (rad)

α : angular acceleration (rad/s²)

t : time interval (s)

ω₀ : initial angular speed ( rad/s)

ωf : final angular speed ( rad/s)

Data

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ω₀= 10.7 rad/s :  initial angular speed of the Wheel ( rad/s)

ωf = 0 : final angular speed  of the Whee( rad/s)

Calculating of the angular acceleration (α )

We replace data in the fómula (1),considering that 1 revolution is equal to 2π radians :

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(0 )²=  (10.7)² + 2*α*(19.5*2*π )

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-114.49 =  (245.04)*α

α= (-114.49) /(245.04)

α= -114.49 /(245.04)

α= -0.467 rad/s²

Time does it take for the bike to come to rest

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10.7  = 0.467*t  

t = 10.7 / 0.467

t = 22.9 s

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