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Ber [7]
3 years ago
7

Scientists have documented that the current level of carbon dioxide in the atmosphere is _________

Physics
1 answer:
Leni [432]3 years ago
7 0
<span>Scientists have documented that the current level of carbon dioxide in the atmosphere is increasing.</span>
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Your mom is making lunch which forces are acting on your mom
N76 [4]

The forces acting on your mom while cooking is Air resistance and the force of friction

<u>Explanation:</u>

<u>1. Air resistance:</u>

  • In simple words, Air resistance can be stated as the type of friction  between the air and the other materials.
  • In this scenario, there will be an air resistance and the air hits the mom while cooking via the doors or windows

<u>2. The force of friction:</u>

  • In simple words, friction can be stated as, the resistance that one surface or object encounters when moving over another.
  • While cooking the food mom would experience the friction since friction is the transfer of heat, and cooking is the process of receiving that heat.

7 0
3 years ago
Read 2 more answers
a liquid with a specific heat of 1900J/Kg° C has 4750 joules of heat energy is added to it. if the temperature increases from 20
GREYUIT [131]
E=mcθ
where E is the energy added,m is the mass,c is the specfic heat capacity and θ is the change in temprature.
making m subject u get E/c<span>θ=m
</span><span>θ=(30-20)=10</span><span>
plugging the values  we get :
</span>\frac{4750}{1900*10}
<span>
solving it we get the answer that is 0.25kg or 250 grams

</span>
8 0
2 years ago
2. Using Graph 2, calculate the net force experienced by the particle between 4 and 6 seconds. The
Trava [24]

Using Newtons Second Law:

F = m×a

F = (0.25 kg)(-2 m/s²)

F = -0.5 N

<h2>The correct option is C</h2>
3 0
2 years ago
HELP PLEASE FOR BRAINLIEST!
anastassius [24]

Answer:

Density = Mass/Volume => Volume = Mass/Density = 12/3.1 = 3.87ml

Explanation:

8 0
2 years ago
Read 2 more answers
A piece of string 2 meters and has a mass of 5g. On one end of the string hangs a 200 g mass. Find the tension of the string and
viktelen [127]

Explanation:

It is given that,

Length of the string, l = 2 m

Mass of the string, m=5\ g=5\times 10^{-3}\ kg

Hanged mass in the string, m'=200\ g=0.2\ kg

1. The tension in the string is given by :

T=m'g

T=0.2\times 9.8

T = 1.96 N

2. Velocity of the transverse wave in the string is given by :

v=\sqrt{\dfrac{T}{M}}

m = M/l

v=\sqrt{\dfrac{Tl}{m}}

v=\sqrt{\dfrac{1.96\times 2}{5\times 10^{-3}}}

v = 28 m/s

Hence, this is the required solution.

4 0
3 years ago
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