Answer:
jk
Explanation:
Lets decompose the initial velocity into its components:
Vi = 2.25 m/s
Vix = Vi x cos(50)
Viy = Vi x sin(50) = 2.25 x sin(50) = 1.724
Then decompose the final velocity:
Vf = 4.65
Vfx = Vf x cos(120)
Vfy = Vf x sin(120) = 4.65 x sin(120) = 4.027
After that we can use:
Vfy = Viy + ay*t
ay = (Vfy - Viy)/t
ay = (4.027 - 1.724) / 8.33
ay = 0.276
Answer:
Explanation:
As we know that when runner is moving on straight track then the net force on his feet is given as
while when runner is moving on circular track then we have
now percentage change is given as
Answer:
Acceleration will be equal to
Explanation:
We have given mass of the car m = 980 kg
Velocity of the car v = 37.4 km/hr = 10.4 m/sec
Power supplied by the engine P = 5500 watt
We know that power is rate of change of energy with respect to time
So
Energy is equal to energy = force × distance
So
From newtons second law force is equal to Force = mass × acceleration
So
So
Answer:
torque on the loop is 0.9812 Nm
Explanation:
given,
circular loop of 200 turns
radius = 65 cm
current in the loop = 85 A
Earth field is pointed north, but at an angle 45.0°
B = 6.15 × 10⁻⁵ T
torque on the loop = ?
using formula
hence, torque on the loop is 0.9812 Nm