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harina [27]
3 years ago
13

A truck heading east has an initial velocity of 6/ms. It accelerates at 2/ms2 for 12 seconds. What distance does the truck trave

l in the given time
Physics
1 answer:
frez [133]3 years ago
4 0

Answer:

216m

Explanation:

As we know S=ut+1/2at^2

S=6×12+1/2×2×12×12

=72+144

=216 m

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a. Of the three experiments that are used to confirm the Big Bang theory, which is the most interesting to you and why?
HACTEHA [7]

Answer:

Explained

Explanation:

Big Bang happened about 13.7 billion years ago. It is most accepted theory of universe creation. Several experiments have confirmed the happening of big bang back then, in promising way. One of this experiment is the red shift experiment. A scientist named Edwin Hubble tried to study the spectrum of stars. He made a shocking revelation that universe is rushing outwards in all directions. Light travelling away registers on the red side. He observed that the distance stars showed red shift in accelerated manner. If the universe is accelerating that means, at one point it would have been smaller, in fact it was as small as an atom, some how it exploded and lead to formation of the expanding universe.

6 0
3 years ago
The law of conservation of mass states that
Jlenok [28]

Hello There!

The law of conservation of mass states that <em>Matter/substances/energy  can not be created or destroyed, it can only be transferred from state to state.</em>

6 0
3 years ago
If I push a box at a constant rate is there friction force acting on it?
yanalaym [24]
Yes, the friction is acting in the opposite direction you are pushing.
3 0
3 years ago
An object is thrown straight up into the air with an initial speed of 8 m/s, and reaches a greatest height of 15 m before it fal
Ugo [173]

Answer:

The value is T_t =  2.5659 \  s    

Explanation:

From the we are told that  

         The initial speed of the object is  u =  8 \  m/s

         The greatest height it reached is  h  =  15 \  m

Generally from kinematic equation we have that

      v^2 =  u^2 + 2gH

At maximum height v  =  0 m/s

So

      0^2 =  8^2 + 2 *  - 9.8 *  H

=>    H  =  3.27 \  m

Here H is the height from the initial height to the maximum height

So the initial height is mathematically represented as  

      s =  h - H

=>    s =  15 - 3.27

=>    s =  11.73 \  m

Generally the time taken for the object to reach maximum height is mathematically evaluated using kinematic equation as follows

            v  =  u + (-g) t

At maximum height v  =  0 m/s

           0 = 8 - 9.8t

=>         t = 0.8163 \  s

Generally the time taken for the object to move from the maximum height to the ground is mathematically using kinematic equation as follows

       h  =  ut_1 + \frac{1}{2}  gt_1^2

Here the initial velocity is  0 m/s given that its the velocity at maximum height

Also  g is positive because we are moving in the direction of gravity  

So

       15  =  0* t  +  4.9 t^2

=>      t_1  =  1.7496

Generally the total time taken is mathematically represented as

          T_t =  t + t_1

=>        T_t =  0.8163  +   1.7496

=>        T_t =  2.5659 \  s            

 

6 0
3 years ago
A computer monitor uses 200 W of power. How much energy does it use in 10 seconds?
gavmur [86]

Answer:

<u>The correct answer is 0.556 Watts</u>

Explanation:

The computer monitor uses 200 Watts of power in an hour, that is the standard measure.

If we want to know, how much energy the computer monitor uses in one second, we will have to divide both sides of the equation into 3,600.

1 hour = 60 minutes = 3,600 seconds (60 x 60)

Energy per second = 200/3600

Energy per second = 0.0556 Watts

Therefore to calculate how much energy is used in 10 seconds, we do this:

Energy per second x 10

<u>0.0556 x 10 = 0.556 Watts</u>

<u>The computer monitor uses 0.556 Watts in 10 seconds</u>

3 0
3 years ago
Read 2 more answers
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