Answer:
The answer to your question is : 521.8 m
Explanation:
Data:
Different heights
Time first object (tfo) = 10.7 s
Time second object (tso)= 14.8 s
Initial speed of both objects(vo) = 0 m/s
a = 9.81 m/s²
Formula:
h = vot + 1/2 (a)(t)² but vo = 0 so, h = 1/2 (a)(t)²
Then, height fo h = 1/2 (9.81)(10.7)² = 561.6 m
height so h = 1/2(9,81)(14.8)² = 1074.4 m
Difference in their heights = 1074.4 m - 561.6 m = 521.8 m
The force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.
<h3>What is force?</h3>
Force is defined as the product of mass and acceleration of an object.
Friction is defined as the force that resists the movement of an object over another.
Therefore, the force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.
Learn more about force here:
brainly.com/question/12970081
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Answer:
The two moments must be the same:
p1=p2
m1v1=m2v2
v2=(m1v1)/m2
v2=(90 kg x 0.9 m/s)/110kg=0.7 m/s
<h2>According to Newton's Third Law:</h2><h3>"For every action,there exists an equal and opposite reaction"</h3>
<h3>So an action force of 50 N to the left, results in a 50 N reaction force to the right.</h3>
<h2>Option A</h2>
