Question

A plane flies at a steady rate of 40 mph while a second plane flies at a steady rate of 100 mph. The planes are 200 miles apart and fly directly toward each other. In how many hours will they meet?

Answer 1

Answer:

$1\ \text{hour}\ 25\ \text{minutes and }12\ \text{seconds}$

Step-by-step explanation:

The combined distance that both planes will cover is 200 miles

Time taken by both planes will be the same (t)

$\text{Distance}=\text{Speed}\times \text{Time}$

So, the combined distance is

$40t+100t=200\\\Rightarrow 140t=200\\\Rightarrow t=\dfrac{200}{140}\\\Rightarrow t=1.42\ \text{hours}=1\ \text{hour}\ 25\ \text{minutes and }12\ \text{seconds}$

They will meet in $1\ \text{hour}\ 25\ \text{minutes and }12\ \text{seconds}$.

Answer 2

Answer: 10/7 hrs

Step-by-step explanation:

Step 1 of 5:Let’s organize the given information. Fill in the Rate column :  

Rate (mph)  Time (h)  Distance (mi)  

1st plane   40

   

2nd plane   100

   

Step 2 of 5:Let x hours be the time it will take them to meet. Complete the chart using the formula : Distance= Rate x Time :  

Rate (mph)  Time (h)  Distance (mi)  

1st plane  40                    x

   

 

2nd plane  100                   x

   

 

Step 3 of 5:We know that the distance between the planes was 200 miles.

Use this to make an equation : 40x+100x=200  

.

Step 4 of 5:Solve the equation :  10/7

Step 5 of 5:Read the problem and answer the question in the problem.

It will take them  

 hours. 10/7 hrs