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2 years ago

7

andrei mananca o pizza in 30 de minute alex in 15 minute iar adrian in 10 minute in cat timp pot manca cei trei baieti impreuna

sase pizze justificati raspunsul

1 answer:

qwelly [4]2 years ago

5 0

30+15+10=55 minutes.

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A large pizza has diameter 36 cm and a medium pizza has diameter 30 cm. What is the difference in area of the pizzas? Round your

vladimir1956 [14]

Answer:

311 $cm^{2}$

Step-by-step explanation:

Taking a pizza to be a circle

Area of big pizza be x abd are of small pizza be y

hence difference = x-y

Area of a circle = $\pi r^{2}$ where r is the radius

taking $\pi$ to be 3.14

hence area x = 3.14 ( $\frac{36}{2}$ * $\frac{36}{2}$ ) = 1017.36

Area y = 3.14 ( $\frac{30}{2}$ * $\frac{30}{2}$ )= 706.5

x-y = 1017.36- 706.5 =310.86 $cm^{2}$

310.86 $cm^{2}$

6 0

2 years ago

How many ways can you make a dollar with 3 quarters 6 dimes and 8 nickels?

melamori03 [73]

Answer:

3

Step-by-step explanation:

3 quarters + 2 dimes + 1 nickel = 1 dollar

6 dimes + 8 nickels = 1 dollar

7 nickels + 2 quarters + 1 dime = 1 dollar

I think that is all, I hope this helps!

8 0

2 years ago

Read 2 more answers

A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.

scZoUnD [109]

Answer: The required ratio will be

$84:1034$

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

$2x=30\\\\x=\frac{30}{2}=15\ inches$

So, Length of AD becomes

$3x=3\times 15=45\ inches$

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

$\frac{30}{2}=15\ inches$

So, Area of semicircle along AB and CD is given by

$2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2$

Radius of semicircle along AD is given by

$\frac{45}{2}=22.5\ inches$

Area of semicircle along AD and BC is given by

$2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2$

And the combined area of the semicircles is given by

$\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2$

Area of rectangle is given by

$Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2$

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

$1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034$

Hence, the required ratio will be

$84:1034$

8 0

2 years ago

Given the quadratic function y=5x^2−2x identify a, b and c.

saw5 [17]

Work shown above! Answer is
a = 5 b = -2 c = 0

6 0

2 years ago

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3(x + y + h)=<br> Can someone help me with this

Nastasia [14]

Answer:

3x +3y +3h

that’s the farthest you can solve since you don’t know the variable’s values

4 0

2 years ago