Answer:
Step-by-step explanation:
Given the points (3, 9) and (9, 1), we must first solve for the slope of the line before proceeding with writing the point-slope form.
In order to solve for the slope (<em>m </em>), use the following formula:
m = (y₂ - y₁)/(x₂ - x₁)
Let (x₁, y₁) = (3, 9)
(x₂, y₂) = (9, 1)
Substitute these values into the given formula:
m = (y₂ - y₁)/(x₂ - x₁)
m = (1 - 9)/(9 - 3)
Therefore, the slope of the line, m = -4/3.
Next, using the slope, m = -4/3, and one of the given points, (x₁, y₁) = (3, 9), substitute these values into the following point-slope form:
y - y₁ = m(x - x₁)
⇒ This is the <u>point-slope form</u>.
Let's say that in the beginning he weighted x and at the end he weighted x-y, y being the number of kg he wanted to loose.
first month he lost
y/3
then he lost:
(y-y/3)/3
this is
(2/3y)/3=2/9y
explanation: ((y-y/3) is what he still needed to loose: y minus what he lost already
and then he lost
(y-2/9y-1/3y)/3+3 (the +3 is his additional 3 pounts)
(y-2/9y-1/3y)/3-3=(7/9y-3/9y)/3+3=4/27y+3
it's not just y/3 because each month he lost one third of what the needed to loose at the current time, not in totatl
and the weight at the end of the 3 months was still x-y+3, 3 pounds over his goal weight!
so: x -y/3-2/9y-4/27y-3=x-y+3
we can subtract x from both sides:
-y/3-2/9y-4/27y-3=-y+3
add everything up:
-19/27y=-y+6
which means
-19/27y=-y+6
y-6=19/27y
8/27y=6
4/27y=3
y=20.25
so... that's how much he wanted to loose, but he lost 3 less than that, so 23.25
ps. i hope I didn't make a mistake in counting, let me know if i did. In any case you know HOW to solve it now, try to do the calculations yourself to see if they're correct!
The greatest common divisor of these numbers is 12.
Rounded to nearest ten--- 950
Rounded to nearest hundred--- 900
A trick you can use for rounding-------- 5 or more, raise the score; 4 or less, let it rest.
X= -7
2+x=-5 if you move the constant to the right side it would be x=-5-2 which equals -7
