Answer:
-1
Step-by-step explanation:
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The function of the area of the square is A(t)=121![t^{2}](https://tex.z-dn.net/?f=t%5E%7B2%7D)
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 ![\frac{cm}{sec}](https://tex.z-dn.net/?f=%5Cfrac%7Bcm%7D%7Bsec%7D)
⇒x=11t
Area of square=![(length of side)^{2}](https://tex.z-dn.net/?f=%28length%20of%20side%29%5E%7B2%7D)
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121![t^{2}](https://tex.z-dn.net/?f=t%5E%7B2%7D)
Therefore,The function of the area of the square is A(t)=121![t^{2}](https://tex.z-dn.net/?f=t%5E%7B2%7D)
Learn more about The function of the area of the square is A(t)=121![t^{2}](https://tex.z-dn.net/?f=t%5E%7B2%7D)
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 ![\frac{cm}{sec}](https://tex.z-dn.net/?f=%5Cfrac%7Bcm%7D%7Bsec%7D)
⇒x=11t
Area of square=![(length of side)^{2}](https://tex.z-dn.net/?f=%28length%20of%20side%29%5E%7B2%7D)
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121![t^{2}](https://tex.z-dn.net/?f=t%5E%7B2%7D)
Therefore,The function of the area of the square is A(t)=121![t^{2}](https://tex.z-dn.net/?f=t%5E%7B2%7D)
Learn more about area here:
brainly.com/question/27683633
#SPJ4
Answer:
Graph A
Step-by-step explanation:
I had this question in my class and got it right with answer A :')
The decimal equivalent of 1/4 is 0.25.
Sum of all angles in a 62 sided polygon = 10800°. (Mark me as brainliest pls!)