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bogdanovich [222]

3 years ago

14

You can drive your car 21.7 miles with one gallon of gasoline. At that rate, how many miles can you drive with 13.2 gallons of g

asoline?
PLEASE ANSWER ASAP

1 answer:

Phantasy [73]3 years ago

3 0

Answer:

286.44 miles........

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In the following question solve for X please help!

Mariulka [41]

Answer:

<u>x = 6</u>

Step-by-step explanation:

Taking the sides in proportion :

EB/DC = AB/AC
8/24 = -3 + 2x/27
1/3 = -3 + 2x/27
3(-3 + 2x) = 27
-9 + 6x = 27
6x = 36
<u>x = 6</u>

8 0

2 years ago

Read 2 more answers

I don’t understand how to do this.

yan [13]

Answer:

46degrees

Step-by-step explanation:

From the question, we are told that both triangles are similar, hence;

<E = <S

<D = <R

<F = <T

From triangle DEF

<D + <F + <E = 180

Since <D = <F = 67

67 + 67 + <E = 180

134 + <E = 180

<E = 180 - 134

<E = 46degrees

Since <E = <S, hence the measure of <S is 46degrees

8 0

3 years ago

Pleaaasee need correct answer! Brainliest(:

larisa86 [58]

Answer:

Choice 4 is the correct answer

7 0

3 years ago

Read 2 more answers

The diagram below shows the dimensions of a triangular park built in a new housing development. Two side lengths and one angle m

evablogger [386]

ANSWER

$x = 50.5 \degree$

EXPLANATION

We use the sine rule for solving triangles.

This is given by the formula,

$\frac{ \sin(A) }{a} = \frac{ \sin(B) }{b} = \frac{ \sin(C) }{c}$

From the triangle,

$\frac{ \sin(x) }{60} = \frac{ \sin(40) }{50}$

We multiply both sides of the equation by 60 to get,

$sin(x) = \frac{ 60\sin(40 \degree) }{50}$

$sin(x) = 0.7713$

We solve for x to obtain,

$x = arcsin(0.7713)$

$x = 50.475$

To the nearest tenth, we round to one decimal place to get,

$x = 50.5 \degree$

7 0

4 years ago

Factorise 9w² - 100<br><br><br>

ohaa [14]

Answer:

$9\, w^{2} - 100 = (3\, w - 10) \, (3\, w + 10)$ .

Step-by-step explanation:

Fact:

$\begin{aligned} & (a - b)\, (a + b)\\ =\; & a^{2} + a\, b - a\, b - b^{2} \\ =\; & a^{2} - b^{2} \end{aligned}$ .

In other words, $(a^{2} - b^{2})$ , the difference of two squares in the form $a^{2}$ and $b^{2}$ , could be factorized into $(a - b)\, (a + b)$ .

In this question, the expression $(9\, w^{2} - 100)$ is the difference between two terms: $9\, w^{2}$ and $100$ .

$9\, w^{2}$ is the square of $3\, w$ . That is: $(3\, w)^{2} = 9\, w^{2}$ .
On the other hand, $10^{2} = 100$ .

Hence:

$9\, w^{2} - 100 = (3\, w)^{2} - (10)^{2}$ .

Apply the fact that $a^{2} - b^{2} = (a - b) \, (a + b)$ to factorize this expression. (In this case, $a = 3\, w$ whereas $b = 10$ .)

$\begin{aligned}& 9\, w^{2} - 100 \\ =\; & (3\, w)^{2} - (10)^{2} \\ = \; & (3\, w - 10)\, (3\, w + 10)\end{aligned}$ .

8 0

3 years ago