Re write it in so that to have one single entity on the left & same on the right
log(x-1)-log5 = log[(x-1)/5]
and log(x+1)-logx = log[(x+1)/x]
So:
log[(x-1)/5] = log[(x+1)/x] ==> (x-1)/5 = (x+1)/x
Now you can solve it: x(x-1)=5(x+1)
==> x² - 6x -5 =0
Solving this quadratic equation gives x'=3+√14 & x" =3-√14
A) True is the answer you are looking for.
Answer:
F and B (as far as I can see).
Step-by-step explanation:
First, let's simplify the equation. You can easily do this by dividing by -4.
-4x < 20
/-4 /-4
x > -5
REMEMBER- Whenever dividing or multiplying a negative number with inequalities, the sign flips!!
On A, we can see that it has a negative symbol, but if we were to divide that, the sign would flip, making -5 greater than x. That's not what we want.
On B, the 20 is negative instead of the 4. Does this change anything?
4x > -20
/4 /4
x > -5
Nope! It still simplifies to what we had at the beginning so it works!
C and D are slightly confusing me because, well, I don't really see how it's relevant to anything so... It doesn't even have a inequality symbol so I don't know lol.
E is wrong because we need the 5 to be positive.
F is obviously right compared to our first answer.
Answer:
35
Step-by-step explanation:
take no. of red footballs be 4x and yellow footballs be 3x
4x=20, x=5
=> 3(5)= 15
total no. of footballs= 20+15= 35