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Bingel [31]
3 years ago
9

Find three consecutive multiples of four such that three times the first one plus four times

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:

8,12 and 16

Step-by-step explanation:

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What is the probability of selecting the letters that spell “FABULOUS” from a hat that contains all the letters of the alphabet,
Andru [333]
FABULOUS=8 letters
Alphabet=26

8/26 * 104

832/27014
3 0
3 years ago
Suppose that during it's flight, the elevation `e` (in feet) of a certain airplane and its time `t,` in minutes since takeoff, a
kifflom [539]

Answer:

Suppose that during its flight, the elevation e (in feet) of a certain airplane and its time ... since takeoff, are related by a linear equation. Consider the graph of this equation, with time represented on the horizontal axis and elevation on the vertical axis. ... Unit 3; Linear Relationships Lesson 9: Slopes Don't Have to be Positive.

Step-by-step explanation:

8 0
3 years ago
Choose the correct answer.
guapka [62]
The correct answer is c but i am not sure

5 0
3 years ago
Uma loja de equipamentos eletrônicos anunciou um celular com duas opções de venda. Na primeira opção, o pagamento pode ser feito
Lena [83]

Responda:

Preço = $ 400

Explicação passo a passo:

Dado que:

Primeira opção :

Pagamento em 5 investimento igual

Segunda opçao :

Pagamento feito em 8 iguais. Investimento

O preço por parcela do primeiro investimento é 30 a mais do que cada um do segundo

Deixe o preço do telefone = p

Valor por prestação = x

Segunda parcela:

Preço = 8x

Primeiro :

Valor por parcela = x + 30

P = 5 (x + 30)

Preço = 5x + 150

Portanto, igualando as duas equações:

8x = 5x + 150

8x - 3x = 150

5x = 150

x = $ 50

Usando qualquer das equações de preço:

Preço = 8x

Preço = 8 * 50

Preço do telefone = $ 400

3 0
3 years ago
How do u factor this
PilotLPTM [1.2K]

You can factor a parabola by finding its roots: if

p(x)=x^2+bx+c

has roots x_1,\ x_2, then you have the following factorization:

p(x) = (x-x_1)(x-x_2)

In order to find the roots, you can use the usual formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

In the first example, this formula leads to

x_{1,2} = \dfrac{-2\pm\sqrt{4+4}}{2} = \dfrac{-2\pm\sqrt{8}}{2} = \dfrac{-2\pm2\sqrt{2}}{2} = 1 \pm \sqrt{2}

So, you can factor

x^2-2x-1 = (x-1-\sqrt{2})(x-1+\sqrt{2})

The same goes for the second parabola.

As for the third exercise, simply plug the values asking

f(1.5)=-5.25

you get

f(-1.5) = 1.5c-3 = -5.25

Add 3 to both sides:

1.5c = -2.25

Divide both sides by 1.5:

c = 1.5

7 0
3 years ago
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