> and>
Step-by-step explanation:
Answer:
An interval that will likely include the proportion of students in the population of twelfth-graders who carry more than $15 is 960
Step-by-step explanation:
For example, Condition 1: n(.05)≤N
• The sample size (10) is less than 5% of the population (millions of musicians), so
the condition is met.
• Condition 2: np(1-p)≥10
• =
2
10
= .2
• 1 − = 10 .2 1 − .2 = 1.6 . This is less than 10 so this condition is not
met.
It would not be practical to construct the confidence interval.
Next time, please include the instructions.
This inequality could be broken into two parts:
4m
m + 9 AND m + 9 > -9 + 4m
Focus first on the inequality m + 9 > -9 + 4m. subtract m from both sides, obtaining:
9 > -9 + 3m. Next, add 9 to both sides, obtaining: 18>3m, or m<6
Last step: Determine whether the inequality <span>4m≥m+9 is true if m<6.</span>
Answer: Choice D)
F(x) > 0 over the inverval (-infinity, -4)
Translation: The y or f(x) values are positive whenever x < -4.
========================================================
Further Explanation:
Recall that y = f(x), so if we say something like f(x) < 0 then we mean y < 0. Choice A is false because points on the curve to the left of x = -4 have positive y coordinates. Similar reasoning applies to choice B as well.
Choice C is false because while the interval (-infinity, -4) is above the x axis, the portion from x = -4 to x = -3 is below the x axis.
Choice D is true because everything to the left of x = -4 is above the x axis. Pick any point on the blue curve that is to the left of x = -4. This point will be above the horizontal x axis. Keep in mind that the parenthesis notation attached to the -4 means we dont include -4 as part of the interval.
