DE + EF = DF
x - 2 + 6x + 4 = 8x - 2
7x + 2 = 8x - 2
2 + 2 = 8x - 7x
4 = x <===
Get her done ...........................
F(x)=|x-5|+2
plug it in
so f(3)
f3)=|3-5|+2
solve whats inside first
|-2|+2
since its absolute value its actually positive
2+2
4
Your answer is C.) 4
Answer:
Letter C: 26
Step-by-step explanation:
Just took the test e2020
