Answer:
4 x^(3/2) + 5x -32
Step-by-step explanation:
This problem involves definite integration (anti-derivatives).
If dy/dx = 6x^(1/2) - 5, then dy = 6x^(1/2)dx - 5dx.
(1/2) + 1
This integrates to y = 6x
----------------
(1/2) + 1 x^(3/2)
= 6 ------------ + C
3/2
or: 4 x^(3/2) + C
and the ∫5dx term integrates to 5x + C.
The overall integral is:
4 x^(3/2) + C + 5x + C. better expressed with just one C:
4 x^(3/2) + 5x + C
We are told that the curve represented by this function goes thru (4, 20).
This means that when x = 4, y = 20, and this info enables us to find the value of the constant of integration C:
20 = 4 · 4^(3/2) + 5·4 + C, or:
20 = 4 (8) + 20 + C
Then 0 = 32 + C, and so C = -32.
The equation of the curve is thus 4 x^(3/2) + 5x -32
(1/2 + 1)
Answer: There are ways of doing this
Hi!
To solve this problem we can think in term of binary numbers. Let's start with an example:
n=5, A = {1, 2 ,3}, B = {4,5}
We can think of A as 11100, number 1 meaning "this element is in A" and number 0 meaning "this element is not in A"
And we can think of B as 00011.
Thinking like this, the empty set is 00000, and [n] =11111 (this is the case A=empty set, B=[n])
This representation is a 5 digit binary number. There are of these numbers. Each one of this is a possible selection of A and B. But there are repetitions: 11100 is the same selection as 00011. So we have to divide by two. The total number of ways of selecting A and B is the .
This can be easily generalized to n bits.
You would first divide 28 by 7.
28 / 7 = 4.
Now multiply 4 by 5.
4 X 5 = 20.
Therefore, Leon read 20 pages.
I suppose <em>K</em> is the matrix
To compute det(<em>K</em>), you can use a simple cofactor expansion along the first row:
Answer:
137/(36π) ft/s
Step-by-step explanation:
The rate of change of volume will be the product of the rate of change of radius and the area of the sphere. The area of the sphere is ...
A = 4πr² = 4π(6 ft)² = 144π ft²
Then the relationship above is ...
dV/dt = A·dr/dt
548 ft³/s = (144π ft²)·dr/dt
dr/dt = (548 ft³/s)/(144π ft²) = 137/(36π) ft/s ≈ 1.2113 ft/s