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Answer:
Empirical formula will be (NH₄)₃PO₄, which matches the molecular formula
Explanation:
This is the reaction:
NH₃ + H₃PO₄ → 28.2% N, 20.8% P, 8.1% H, 42.9% O
In 100 g of compound we have:
28.2 g N
20.8 g of P
8.1 g of H
42.9 g of O
Now we divide each between the molar mass:
28.2 g / 14 g/mol = 2.01 mol
20.8 g / 30.97 g/mol = 0.671 mol
8.1 g / 1 g/mol = 8.1 mol
42.9 g / 16 g/mol = 2.68 mol
And we divide again between the lowest value of moles
2.01 mol / 0.671 mol → 3
0.671 mol / 0.671 mol → 1
8.1 mol / 0.671 mol → 12
2.68 mol / 0.671 mol → 4
Molecular formula will be: N₃PH₁₂O₄ → (NH₄)₃PO₄
Empirical formula will be (NH₄)₃PO₄, which matches the molecular formula
Answer:
The value of 
at 4224 K is 314.23.
Explanation:
Initially
4.97 atm 0
At equilibrium
4.97 - p 2p
At initial stage, the partial pressure of oxygen gas = =4.97 atm
At equilibrium, the partial pressure of oxygen gas = 
So, 4.97 - p = 0.28 atm
p = 4.69 atm
At equilibrium, the partial pressure of O gas = 
The expression of is given as :
The value of at 4224 K is 314.23.
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