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tatiyna
3 years ago
14

Find a polynomial f(x) of degree 4 that has the following zeros. 2, 5, 0, -7

Mathematics
1 answer:
Otrada [13]3 years ago
6 0

Answer:

Step-by-step explanation:

f(x) = (x - 2)(x - 5)x(x+ 7)

f(x) = (x^2 - 7x + 10)*x * (x + 7)

f(x) = x(x^3 - 39x + 70)

f(x) = x^4 - 39x^2 + 70x

To show that this is correct, I've made a graph with these points labeled. The graph is just around the x axis. The local maximums and minimums are just too large a value.

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Chris ran 25 miles, while Bill ran 5 miles. How many times farther did Chris run than Bill?
mixer [17]

Answer: Chris ran 20 miles more then Bill

Step-by-step explanation:

25(Chris) - 5(Bill) = 20 Miles

Hope this helped, have a great day/night!

~IFoundJiminsLostJams~

8 0
3 years ago
Read 2 more answers
What’s the correct answer for this?
dybincka [34]

Answer:

(A)

Step-by-step explanation:

Using the formula :

Area = 1/2 [-1(1 - 6) -7(6 - 1) -3(1 - 1)]

Area = 1/2 [5 - 35]

Area = 1/2 × -30 = |-15| = 15 units²

5 0
3 years ago
The body weight of a healthy 3 month-old colt should be about μ = 60 kg. (Source: The Merck Veterinary Manual, a standard refere
tatuchka [14]

Answer:

a

  The null hypothesis will be  H_o : \mu = 60 \ kg

b

  The alternative hypothesis will be  H_a : \mu <  60

c

  The alternative hypothesis will be  H_a : \mu >  60

d

  The alternative hypothesis will be  H_a : \mu \ne   60

e

  left; right; both

Step-by-step explanation:

Considering question a

    The body weight of the colt is  \mu = 60 \ kg

    The null hypothesis will be  H_o : \mu = 60 \ kg

Considering question b

    Given that we want to test the claim that the average weight of a wild Nevada colt is less than 60 kg , then

The alternative hypothesis will be  H_a : \mu <  60

Considering question c

       Given that we want to test the claim that the average weight of such a wild colt is greater than 60 kg , then

The alternative hypothesis will be  H_a : \mu >  60

Considering question d

   Given that we want to test the claim that the average weight of such a wild colt is different from 60 kg , then

The alternative hypothesis will be  H_a : \mu \ne   60

Considering question e

   For question b  , the corresponding p-value will be on the left because the average weight is less than 60 kg

   For question c  , the corresponding p-value will be on the right  because the average weight is more than 60 kg

   For question d  , the corresponding p-value will be on both  because the average weight is different from  60 kg

5 0
2 years ago
In a school band, the ratio of student late who play the tuba to the students who play the trumpets is 1:6. The ratio of student
AlexFokin [52]
A lot, 1:6 + 3:4 +3 = .116789465 hope this helps....
7 0
3 years ago
Can someone please help. Please show work
FinnZ [79.3K]

Answer:

11. parallelogram, rectangle

12. parallelogram, rhombus

13. parallelogram, square

5 0
3 years ago
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